TBR physics Lecture 2 ?

[unDRdog]

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I would type the question but its a graph----P73 Example 2.4b of the Physics 1 book...(relationship bt tension and acceleration)...any explination would help....thanks

 

[phEight]

I would type the question but its a graph----P73 Example 2.4b of the Physics 1 book...(relationship bt tension and acceleration)...any explination would help....thanks

Well, I would say the tension force is simply = to mass*acceleration. There are no squares, or square roots for this force, so it implies the graph should be linear. Also, the question states the cable is used to support and move the elevator, so that means even when the acceleration goes to 0, there is still tension in the cable because it is supporting the elevator. Which leads us to answer choice A.

I think that's about right...

 

[unDRdog]

Well, I would say the tension force is simply = to mass*acceleration. There are no squares, or square roots for this force, so it implies the graph should be linear. Also, the question states the cable is used to support and move the elevator, so that means even when the acceleration goes to 0, there is still tension in the cable because it is supporting the elevator. Which leads us to answer choice A.

I think that's about right...

Thanks phEight---is that a safe trick to use when faced with these graphy ?;s ( If there are squares, square roots , then the graph will not be linear and look more like graph B?)

 

[phEight]

Thanks phEight---is that a safe trick to use when faced with these graphy ?;s ( If there are squares, square roots , then the graph will not be linear and look more like graph B?)

Yep, I would say so... except also remember that inverse relationships won't be linear either. Here is a square root graph. Usually a good idea to know how these look so you can easily identify them..