Tbr titration table 5.3

[yellowjellybean]

Advertisement - Members don't see this ad

Hey guys,

Can someone explain to me the last two rows? How is it that "the pOH is found by taking the negative log excess of [OH-] which can be quickly found using [OH-]initial x [(mL OH- minus 50)/(mL OH- +50)]?

Thank you

 

[Sammy1024]

I'm not sure where this problem is BUT...

pOH = -log [OH] <== an equation to remember

I'm assuming that there was a table, and then you mixed in 50mL of stuff and it reacted to form some compound. So in that case you have the original compound of X + concentration of the 2nd compound and then underneath they subtracted -50mL that was reacted. Sorry for not being too helpful. You should put more data?