Tert butyl alcohol + HCl and ZnCl2

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reising1

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In reacting tert butyl alcohol (or any alcohol that undergoes SN1) with HCl and ZnCl2 it seems that the purpose of the ZnCl2 is to activate the alcohol and make it a better leaving group.

If it was an acid, I would understand this, because the OH could be protonated and then leave as water. But how does ZnCl2 activate the alcohol exactly?

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In reacting tert butyl alcohol (or any alcohol that undergoes SN1) with HCl and ZnCl2 it seems that the purpose of the ZnCl2 is to activate the alcohol and make it a better leaving group.

If it was an acid, I would understand this, because the OH could be protonated and then leave as water. But how does ZnCl2 activate the alcohol exactly?


I do believe Zn2+ acts as a Lewis acid.
 
But it doesn't donate a proton so how does this make the OH a better leaving group? It just leaves as OH-?
 
But it doesn't donate a proton so how does this make the OH a better leaving group? It just leaves as OH-?

Fairly certain that the HCl (a stong acid) dissociates into H+ and Cl-. The OH- picks up the hydrogen and is now H2O, a good leaving group. The newly formed tertiary carbocation now reacts with the ZnCl2 to give t-butyl chloride.
 
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Fairly certain that the HCl (a stong acid) dissociates into H+ and Cl-. The OH- picks up the hydrogen and is now H2O, a good leaving group. The newly formed tertiary carbocation now reacts with the ZnCl2 to give t-butyl chloride.

I thought he meant that both of the reagents were being used separately, not together.
 
They are being used together. The purpose of the ZnCl2 is to activate the alcohol (as per Examkrackers), not to add to the tert butyl.
 
ZnCl2 is your lewis acid in this situation, while the -OH will be your lewis base.

Firstly, you'll form a bond between OH and ZnCl2 giving you H -- O(+) -- (-)ZnCl2
This will basically add a degree of resonance to your Alcohol, allowing it to become a better leaving group. From here, Cl- from the dissociation of HCl will come in and attack the newly form carbocation, adding Cl.

If you're more of a visual person, this is drawn out here (Slide 20): http://www.utdallas.edu/~biewerm/11alc.pdf

And here (Page 7):
http://crab.rutgers.edu/~alroche/Ch11.pdf
 
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