ok how about this one:
answer:b
So the answer is B, okay that's what I got when I worked it out. Now for me I tend to do the line-counting method in addition to visualizing it in 3-d. Based on the answer choices provided I looked at the smaller diamond shape, since it is easier to rule out possible answers with a simpler object. The top view gives a shorter width to the shape, and the front view indicates a longer height. So the diamond is oriented with it having a shorter width and longer height, or that it is in a vertical position. This would instantly eliminate answer C. Now we can check if it is attached to the rod at the top of the diamond or the bottom. Again, the front view shows us that the diamond is hanging below the bigger object, so answer D is eliminated.
Now for the trickier part. We are left with answer choices A and B. The top view shows us that the object has 3 edges at its top face. Answers A and B both have that, so no real help there. However, the front view tells us something very important. There is a dashed line through the center of the front view, meaning that one of the edges is hidden if you look at it from the front face. If you look at the hexagon in answer A, each edge on the hexagon is parallel to the other edge and thus no edges are hidden from any way you orient it. However, if you look at the pentagon in answer choice B from a front view, you can see that the opposite vertex to an edge is hidden. Thus, it would appear as a dashed line in a front-view setting. This matches the front view in our problem, and thus we arrive at answer choice B.
To help illustrate what I'm talking about, imagine a pentagon lying flat on a table. Now if you kneel down and level your sight to the side of a pentagon you will see a rectangle. However, behind that rectangle on the other side of the pentagon is a hidden vertex. So in terms of TFE, the rectangle you see will have a dashed line going vertically down the middle of it, similar to the front view in this problem.
My method with TFE is to eliminate answer choices that are completely random. Then I work it down using line counting. If the line counting doesn't help me out much, then I look at any differences in the (usually) two options I am left with. I try to imagine it in 3-d to help me understand why one answer is better than the other. In this case, line counting works quite nicely.