Thermodynamics?

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alex1231

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Hi,
Can anybody explain this problem to me?
I have a 50 gm of a metal which has a specific heat of 0.25 cal/gm. It is heated to 100 Celcius. I put it in a water which was initially at 25 Celcius. What is the equilibrium temperature?
I used q=m(c)dT where dT=(Tf-Ti).
q(metal)=q(water) where c(water)=1cal/gm
50(0.25)(Tf-100)=50(1)(Tf-25)
When I looked at the solution for this problem they had:
50(0.25)(100-Tf)=50(1)(Tf-25)
Can anybody explain why (100-Tf) instead of (Tf-100)?
Thank you!
 
This is because the heat LOST by the metal is GAINED by the water
One of them has a negative heat change while the other has a positive heat change.
So there's a negative sign jumping around and the solution just simplified that negative sign in to 25-Tf instead of -(Tf-25)
Hope that helps
Good luck
 
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