does anyone know intercondylar distance and steepness of articulat eminancce have to do whit height of cusp or depth of fossa?
and height of cusp in horizontal overlap?
what is the refrence for occlusion in NBDE 1😕
Think of this as simple geometry. Steeper inclines mean that on protrusive and ipsolateral excusive movements the mandble will disarticulate more as the movement progresses from midline or rest than if the incline is shallow. With that in mind and regarding cusp tip heights, a steeper eminence can accomadate
equal or less steep cusp inclines and higher rather than flatter cusp heights. On the other hand, shallower angled eminence can only allow for
as shallow or shallower cusp inclines and flatter cusp morphology. In general, think shallow eminence angle correlates to flatter cusps and steeper eminences correlate to the possiblilty of taller cusps and steeper inclines.
Treat intercondylar distance as a radius measurement, closer intercondylar dist means tighter rotation around the axial axis of the working condyle with orbiting of the non-working condyle anteriorly and medially down the eminence. If the radius is small and eminence is steep, cusps tend to be steeper and closer together. In larger radius (larger intercondylar dist) and shallower eminence slopes, cusps will be flatter and further apart.
Hope this helps, if you get the core concept and make it logical for yourself, you can avoid complex memorization for test day.
