-
CycleTrack and SDN are teaming up to make medical school admissions more transparent and accessible! Read the announcement to learn how we’re supporting the future of CycleTrack’s free application-tracking tools .
TopScore Exam 1 QR Question #12
Started by ILikeTeeth
Get help with your application
Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.
On this one, you need to find the area of the circle first using pi*radius^2. This gives you 16 pi.
Next, find the area of the square. This is tricky because you only have the radius of the circle to work with, but it gives you two of the leg of the triangle, each with equals 4. This only leaves the hypontenuse to discover which is a^ + b^2 = c^2, so 4^2 + 4^2 = c^2. This ends up to be c^2 = 32, or c = square root of 32.
Now you have one leg of the square, which means you can find the area by squaring this value, so square root of 32 ^2 = 32.
Now you have the area of the circle, but you want to subtract the area of the square, so you end up with 16 pi - 32. The folks on test won't expect you to reduce pi using decimals, which is nice.
Hope that makes sense.
Next, find the area of the square. This is tricky because you only have the radius of the circle to work with, but it gives you two of the leg of the triangle, each with equals 4. This only leaves the hypontenuse to discover which is a^ + b^2 = c^2, so 4^2 + 4^2 = c^2. This ends up to be c^2 = 32, or c = square root of 32.
Now you have one leg of the square, which means you can find the area by squaring this value, so square root of 32 ^2 = 32.
Now you have the area of the circle, but you want to subtract the area of the square, so you end up with 16 pi - 32. The folks on test won't expect you to reduce pi using decimals, which is nice.
Hope that makes sense.
Similar threads
