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- Nov 9, 2006
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okay q from topscore..
1. 14.250 moles of PCl5 gas in 3.00 L is in equlibrium at constant temp,
40% of the PCl5 decopme according to equation
PCl5(g) <-> PCl3(g) + Cl2(g)
answer was a.(1.896)^2/2.854
not e. None of these
and my question is if I get the Molarity, 14.25/3 M and to get each PCl3 and Cl2, I mutipled the Molarity(4.75M) by .40 and got 1.90
but answer was the 'a' not 'e'
Is real DAT like that?, making people confused by giving the value close to the answer even though all the calculation gives the clear-cut number?
2. Is radica part of conjugated pi orbitals if we want to find the aromaticity?
3. I think this answer is wrong in topscore
Q. the solubility product constant, Ksp for BaCl2?
If I use the formula from kaplan, it must be [Ba2+][Cl-]^2
since equation is BaCl2(s) -> Ba2+ + 2*Cl-
but answer was [Ba2+][Cl2-]
1. 14.250 moles of PCl5 gas in 3.00 L is in equlibrium at constant temp,
40% of the PCl5 decopme according to equation
PCl5(g) <-> PCl3(g) + Cl2(g)
answer was a.(1.896)^2/2.854
not e. None of these
and my question is if I get the Molarity, 14.25/3 M and to get each PCl3 and Cl2, I mutipled the Molarity(4.75M) by .40 and got 1.90
but answer was the 'a' not 'e'
Is real DAT like that?, making people confused by giving the value close to the answer even though all the calculation gives the clear-cut number?
2. Is radica part of conjugated pi orbitals if we want to find the aromaticity?
3. I think this answer is wrong in topscore
Q. the solubility product constant, Ksp for BaCl2?
If I use the formula from kaplan, it must be [Ba2+][Cl-]^2
since equation is BaCl2(s) -> Ba2+ + 2*Cl-
but answer was [Ba2+][Cl2-]