Topscore Test 1 Math question # 12

Discussion in 'DAT Discussions' started by Awuah29, Apr 17, 2007.

1. Awuah29 Christian predent

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Heh guys,

Shouldn't the solution to # 12 Math Test 1 Topscore be
16pi-64?

Ok, Area of square is X^2 radius=4 diameter=8

so area of rectangle= 8^2 =64

area of circle= Pi r^2 so pi 4^2 = 16

I am missing here a something? Anyone , please check it out and let me know

3. Streetwolf Ultra Senior Member Dentist

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I'm assuming the square is outside of the circle. Then it should be 64 - 16pi.

4. Awuah29 Christian predent

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Heh streetwolf,
what do you mean if square is outside? the square is inside and the solution is 16 pi -32, but why? don't get it

5. Benoir

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I'm not sure if this is right, and it would help if the entire problem was given.

Assuming....
The square is inscribed inside of the circle.

So...
The radius line should touch a point on the square and the circle.
The radius lines going to two adjacent corners form a 90 degree angle.
a^2 + b^2 = c^2 and c is one of the sides.

One of the sides of the square is equal to (r^2 + r^2)^0.5, but since you are going to multiply it by itself anyway....
(r^2 + r^2)^0.5 * (r^2 + r^2)^0.5 = Area of the square = (r^2 + r^2)

(4^2 + 4^2) = 32

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