Topscore test 2 chem question 68

Started by dental881
This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

dental881

Full Member
10+ Year Member
Advertisement - Members don't see this ad
I didn't understand their math.

This is the question.
"What volume of HCl was added if 20mL of 1M NaOH is titrated with 1M HCl to produce pH=2.

The answer is 20.4.
Can anyone explain it?
 
Is it multiple choice?

Since the molarities are the same, if you added 20 ml of HCl you'd have a solution with a pH of 7.

Since 1 M HCl has a pH of 0 though (100 times more H3O+ than pH 2), you don't want to add much more than that.

If they actually want you to calculate it out instead of just estimating the obvious answer choice, just be aware that the HCl and NaOH "cancel out" since it's a neutralization, and then find the H3O+ concentration only factoring in the extra acid (0.4 ml). In this case working backwards from a plausible answer is much faster than working forwards to an unknown solution.
 
yea thats how I tried solving it. 20ml of HCl will neutralize it so the pH would be 7 and I thought additional 10ml of 1 M HCl (0.01 molarity) will be needed to reach the pH of 2. Since -log(1*10-2 ) would give pH of 2.
 
Advertisement - Members don't see this ad
Okay i just worked through topscore’s disgusting explanation. We know that we half to add at least 20ml to get the pH around 7. So total volume is 40+x. x is the amount of HCl we’re looking for. So now we set up M1V1=M2V2. (1M of HCl)(x mL)=(.01M[we get this from the pH=2, bc –log of .01 = 2])(40+x mL). so its (1)x=(.01)(40+x), now solve for x. x=.4mL and thus the final amount is 40.4mL. To get just HCl mL subtract the 20mL of NaOH, leaving you with 20.4mL. I hope that helped!
 
yea thats how I tried solving it. 20ml of HCl will neutralize it so the pH would be 7 and I thought additional 10ml of 1 M HCl (0.01 molarity) will be needed to reach the pH of 2. Since -log(1*10-2 ) would give pH of 2.

an additional ten would give you 50 ml of solution. Solve for moles of H+ and divide by TOTAL liters for the new concentration.