Trig Question from Destroyer Q# 75

[Surive123]

Hey everyone,

This is in reference to question 75 found in the 2011 version of the destroyer. (QR section)

Evaluate ln|tan theta|:

Answer being = ln|sin theta| - ln|cos theta|

Either I am missing the boat here or I just need a break as I am nearing a good 5 hour practice problem sesh.

If anyone could point me in the right direction, I'd appreciate it! Thank you!

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[tmaxwell13]

tan=sin/cos

Division involving ln= subtract
multiplication involving ln= addition

so ln(tan)=ln(sin/cos)=sin-cos

 

[Surive123]

tan=sin/cos

Division involving ln= subtract
multiplication involving ln= multiply

so ln(tan)=ln(sin/cos)=sin-cos

Herp Derp. That's right. Man it's been awhile since HS math.