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Trouble with a math problem
Started by rinsterman12
The problem is (.01)^2 [(.16)^1.2 +4.5)/.003
What I do is convert everything into a fraction and I get 163, but the answer is .16. Help I have no clue what I am doing wrong.
you got it.. just convert it back into fraction again.
When I look at this answer I see something that should be larger than what I am getting. Could you show me the algebra? Just the part converting it back into a decimal and the rational behind that. I am terrible at math as you can see.
Your parentheses aren't matching, I'm having a hard time deciphering what the problem is
and tell how you calculated 1.2 power, because even when you convert it to a fraction 6/5 = 6 * (1/5), I can't calculate the 5th root of something off the top of my head
and tell how you calculated 1.2 power, because even when you convert it to a fraction 6/5 = 6 * (1/5), I can't calculate the 5th root of something off the top of my head
Last edited:
(.01)^2 (.16)^1.2 +4.5) /.003 This is the problem. The answer to the problem is 163, but the DAT online test says the answer is .163. I just want to know why you divide the final answer by 1000 to yield 0.163.
What you might be doing wrong is when squaring the .1 you might not be getting .0001. That might throw you off.
[((.1)^2)((.16^1.2)+4.5)]/(.003)
So, (.1)^2 = .0001
(.16^1.2) + 4.5 ~ .11 + 4.5 = 4.61
.0001 * 4.61 = 0.000461
.000461/.003 ~ .16
I don't know how the DAT works, but for the MCAT I just rounded and approximated all the numbers since we can not use a calculator.
[((.1)^2)((.16^1.2)+4.5)]/(.003)
So, (.1)^2 = .0001
(.16^1.2) + 4.5 ~ .11 + 4.5 = 4.61
.0001 * 4.61 = 0.000461
.000461/.003 ~ .16
I don't know how the DAT works, but for the MCAT I just rounded and approximated all the numbers since we can not use a calculator.
What you might be doing wrong is when squaring the .1 you might not be getting .0001. That might throw you off.
[((.1)^2)((.16^1.2)+4.5)]/(.003)
So, (.1)^2 = .0001
(.16^1.2) + 4.5 ~ .11 + 4.5 = 4.61
.0001 * 4.61 = 0.000461
.000461/.003 ~ .16
I don't know how the DAT works, but for the MCAT I just rounded and approximated all the numbers since we can not use a calculator.
Im not sure what your talking about here...squaring .1 doesnt give you .0001, it gives you .01
also it could be that the answer is wrong, have you used a regular calculator just to make sure? Try that. anyways from the looks of it....the number looks to be big according to the problem. Your going to get a numerator thats less than 5, and the denominator will be .003...
if you divide 5 by .003 your going to get a number thats like 1500+ (since your dividing essentially 5000/3)
sorry i meant squaring .01 from the original question. That gives you 0.0001.
Now that problem will work, I just copied it wrong.
Now that problem will work, I just copied it wrong.
[((.01)^2)((.16^1.2)+4.5)]/(.003)
So, (.01)^2 = .0001
(.16^1.2) + 4.5 ~ .11 + 4.5 = 4.61
.0001 * 4.61 = 0.000461
.000461/.003 ~ .16
Like that above, my apologies.
So, (.01)^2 = .0001
(.16^1.2) + 4.5 ~ .11 + 4.5 = 4.61
.0001 * 4.61 = 0.000461
.000461/.003 ~ .16
Like that above, my apologies.
[((.01)^2)((.16^1.2)+4.5)]/(.003)
So, (.01)^2 = .0001
(.16^1.2) + 4.5 ~ .11 + 4.5 = 4.61
.0001 * 4.61 = 0.000461
.000461/.003 ~ .16
Like that above, my apologies.
how did you calc this with hand?
I knew that:
.16^1 = .16
.16^1.5 = .064
.16^2 = .0256
So, .16^1.2 = something between .16 and .064, so I picked something in between which happens to be .11. I just estimated that number, not sure what the exact number is, but I think it is close enough. I guess I could have also picked .12 or .10, it should not have had too much of a difference.
.16^1 = .16
.16^1.5 = .064
.16^2 = .0256
So, .16^1.2 = something between .16 and .064, so I picked something in between which happens to be .11. I just estimated that number, not sure what the exact number is, but I think it is close enough. I guess I could have also picked .12 or .10, it should not have had too much of a difference.
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