vant hoff factor of MgCl2

[spoog74]

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Is the vant hoff factor for MgCl2 3 or 2?

Im asking because a question goes;

in which of the following solutions will AgCl be least soluble?

.08 M of MgCl2

.15 M AgNO3

or .1 M of HCl

Now i know the answer should be the one with the most concentration of ions of Mg or Cl

 

[Jab1113]

Is the vant hoff factor for MgCl2 3 or 2?

Im asking because a question goes;

in which of the following solutions will AgCl be least soluble?

.08 M of MgCl2

.15 M AgNO3

or .1 M of HCl

Now i know the answer should be the one with the most concentration of ions of Mg or Cl

its 3 because you have 2Cl ions and 1Mg

 

[spoog74]

its 3 because you have 2Cl ions and 1Mg

then why is the answer to this question AgNO3?

 

[JamesBourne]

Is the vant hoff factor for MgCl2 3 or 2?

Im asking because a question goes;

in which of the following solutions will AgCl be least soluble?

.08 M of MgCl2

.15 M AgNO3

or .1 M of HCl

Now i know the answer should be the one with the most concentration of ions of Mg or Cl

MgCl2 i = 3, .08*3 = .24M
AgNO3 i = 2, .15*2 = .30M the most conc. of common ion, thus least solubility
HCl i = 2, .1*2 = .20M

 

[bharat008]

MgCl2 i = 3, .08*3 = .24M
AgNO3 i = 2, .15*2 = .30M the most conc. of common ion, thus least solubility
HCl i = 2, .1*2 = .20M

I always thought that you compare each of the ions.
For example, AgCl is soluble in .15M AgNO3 so you just take the van hoff factor of Ag which is 1; therefore it would be .15M of Ag+ concentration
If you have .08M MgCl2; then Cl concentration would be 2 times .08 = which would give us 0.16M... Since .16 is higher than .15M therefore AgCl would be least soluble in MgCl2..

But thanks for clarifying this concept.. I would have messed up if i had this question on DAT.. 👍

 

[lyjw88]

I always thought that you compare each of the ions.
For example, AgCl is soluble in .15M AgNO3 so you just take the van hoff factor of Ag which is 1; therefore it would be .15M of Ag+ concentration
If you have .08M MgCl2; then Cl concentration would be 2 times .08 = which would give us 0.16M... Since .16 is higher than .15M therefore AgCl would be least soluble in MgCl2..

But thanks for clarifying this concept.. I would have messed up if i had this question on DAT.. 👍

I thought this was correct??

 

[HannibalLecter]

Yup confirming what Bourne said

 

[Seahawk]

Yup confirming what Bourne said

👍

 

[predentlove]

MgCl2

I thought the charge on Mg was 2.. so why would there be 2 Cl ions?

 

[predentlove]

Nvm, I think that just means 3 Cl ions bonded to the Mg. My B.