You increased the enzyme concentration? Most Vmax values are given in "mol of product produced/s" so I'm not sure where the enzyme conc its in with that. I mean, obviously, you're going to be producing MORE moles of product/s with more enzyme but would it be correct to say that Vmax has increased? If you think about it, the Vmax for any particular enzyme is still the same (it still has the same efficiency)
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Doesn't VMAX assume a standardized concentration of catalyst, likely 1 mole and VMAX values are actually moles of product produced per unit time per mole enzyme?
Vmax is in direct relation to the enzyme concentration. More enzyme = higher Vmax because there are more active sites for substrate to bind to. That increases the potential maximum rate of reaction.
Yup, this is why noncompetitive inhibition lowers Vmax; it basically "lowers" the concentration of the enzyme.
i have a question...when reaction reachs the vmax...at this point that the reaction is independent of substrate concentration and dependent on enzyme conc because all enzymes are saturated with the substrates and it gives a certain km value...and i am agree till this till now..but when we increase enzyme concentration to get more products if the body need more products by increase gene expression of this particular gene...so when we get to increase the enzyme concentration it leads to increase of vmax BUT IT TELLS THAT KM WILL NOT CHANGE..howww??!!!it suppose that we got higher enzymatic effect and higher vmax so should km be lower than the 1st value above....!!
PLZ ANY CAN ANSWER ME..
PLZ ANY CAN ANSWER ME..
Km has nothing to do with the amount of enzyme. It is a measure of the affinity of the enzyme for the substrate (similar to Kd for a ES complex).