why Na2SO4 dissociate into 3 while NaNO3 dissociate into 2?

Started by atlanta213
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Hey guys!
Why Na2SO4 dissociate into 3 while NaNO3 dissociate into 2?

Na2SO4 dissociates into 3 ions becasue in water it results in 2Na+ and SO42-. Likewise, NaNO3 results in Na+ and NO3-.

Remember, you have to add the coefficients of the ions to get the sum of all ions.
 
Thanks for reply. I asked this question regarding destroyer genchem 18.

Na2SO3 -> I=3

According to Destroyer, I is # of particles that can theoretically dissociate.

Is this same as what you did? total number ions?

Thanks
 
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Take the molecule and split it up as follows:

Na2SO4 ----> 2Na+ + SO4^2-

Count the moles on the right and divide by the moles on the left, which is 2 +1 = 3

This is fairly important when your using colligative properties...if the compound dissociates in solvent then you need to know the vont-hoff factor...in this example our vont-hoff factor is 3