What's the ph of 10^-8 M of HCl
Can you explain more how you get that 10^-7...( I know it's water)...The OP did not say that HCl dissociates in water. I would think the pH is 8.[H] in water is 10^-7
HCl will dissociate completely, so you'll have [H]=10^-7+10^-8=1.1*10^-7
-log(1.1*10^-7)=6.96
If you need just a quick estimate, it's safe to assume that it's 7 or just a bit below that.
Can you explain more how you get that 10^-7...( I know it's water)...The OP did not say that HCl dissociates in water. I would think the pH is 8.
[H] in water is 10^-7
HCl will dissociate completely, so you'll have [H]=10^-7+10^-8=1.1*10^-7
-log(1.1*10^-7)=6.96
If you need just a quick estimate, it's safe to assume that it's 7 or just a bit below that.
Quick estimate is what I'm looking for! Thx!
Theoretically, it should be. But you have to dissolve it in something, so you need to add in water's acidity. When they say "HCl is a strong acid because it dissociates completely," they mean in water.
I honestly don't know what would happen if you dissolved it in like diethyl ether or something. But unless it says otherwise, assume the solvent is water.
Water is acidic enough that the pH will stay 7, minimal amounts of HCl won't change it.
Ether has pKa significantly higher than 8 which means that HCl will be the major source of H+ and the pH should be 8. Unlike aqueous solutions, pH of 8 will not indicate a basic solution here - neither Cl-, nor ether are good proton acceptors.
Can you explani why a pH of 8 doesn't indicate a basic solution? I mean, I know HCl is a strong acid...
I would never have expected a situation where HCl has a pH of anywhere near 7-8
Ether has pKa significantly higher than 8 which means that HCl will be the major source of H+ and the pH should be 8. Unlike aqueous solutions, pH of 8 will not indicate a basic solution here - neither Cl-, nor ether are good proton acceptors.