Orgo destroyer question

Started by dp93
This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.
Get help with your application

Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.

dp93

Full Member
10+ Year Member
Advertisement - Members don't see this ad
someone explain this question. I'l post the answer in the next comment.
 

Attachments

  • photo (4).JPG
    photo (4).JPG
    77.5 KB · Views: 197
Advertisement - Members don't see this ad
The answer is B, because you have 4 different signals, for 4 different carbons. Peak at 0 does not count because it is a solvent. In choice B, there are two methyl groups that are attached to the same carbon. They will show only one signal.