D dp93 Full Member 10+ Year Member Joined Jan 23, 2013 Messages 340 Reaction score 211 Apr 13, 2014 #1 Members don't see this ad. someone explain this question. I'l post the answer in the next comment. Attachments photo (4).JPG 77.5 KB · Views: 108
D dp93 Full Member 10+ Year Member Joined Jan 23, 2013 Messages 340 Reaction score 211 Apr 13, 2014 #2 Its supposed to be B....HOW IS IT NOT E??!?! Upvote 0 Downvote
D dp93 Full Member 10+ Year Member Joined Jan 23, 2013 Messages 340 Reaction score 211 Apr 13, 2014 #3 anyone?? Upvote 0 Downvote
SmileDesignersDDS Full Member 7+ Year Member Joined Mar 22, 2014 Messages 199 Reaction score 30 Apr 13, 2014 #4 It's def not E lol. Look there are 4 signals. So it could be B but def not E. On E there are way too many carbon signals Upvote 0 Downvote
It's def not E lol. Look there are 4 signals. So it could be B but def not E. On E there are way too many carbon signals
D dp93 Full Member 10+ Year Member Joined Jan 23, 2013 Messages 340 Reaction score 211 Apr 13, 2014 #5 SmileDesignersDDS said: It's def not E lol. Look there are 4 signals. So it could be B but def not E. On E there are way too many carbon signals Click to expand... i count 5 signals? There is 5 peaks.... Upvote 0 Downvote
SmileDesignersDDS said: It's def not E lol. Look there are 4 signals. So it could be B but def not E. On E there are way too many carbon signals Click to expand... i count 5 signals? There is 5 peaks....
Potential22 Full Member 7+ Year Member Joined Mar 18, 2014 Messages 32 Reaction score 2 Apr 13, 2014 #6 only four peaks the small peak at the beginning is not related to the compound Upvote 0 Downvote
T tcufrof824 Full Member 7+ Year Member Joined Dec 15, 2013 Messages 32 Reaction score 14 Apr 13, 2014 #7 As PotentialDentist16 mentioned, there are only 4 carbon peaks. The small peak at 0 is due to the solvent used. Upvote 0 Downvote
As PotentialDentist16 mentioned, there are only 4 carbon peaks. The small peak at 0 is due to the solvent used.
B biomolecmed Full Member 10+ Year Member Joined Apr 7, 2012 Messages 1,014 Reaction score 79 Apr 13, 2014 #8 The answer is B, because you have 4 different signals, for 4 different carbons. Peak at 0 does not count because it is a solvent. In choice B, there are two methyl groups that are attached to the same carbon. They will show only one signal. Upvote 0 Downvote
The answer is B, because you have 4 different signals, for 4 different carbons. Peak at 0 does not count because it is a solvent. In choice B, there are two methyl groups that are attached to the same carbon. They will show only one signal.