- Joined
- Apr 19, 2016
- Messages
- 226
- Reaction score
- 139
Hey, so from my understanding the stop codons on RNA are 5'-UAA/UGA/UAG-3'.
Consequently, the DNA is supposed to then have in its sequence 5'-TAA/TGA/TAG-3', which corresponds to stop codons.
However, I'm getting slightly confused how this sequence goes from DNA to mRNA.
For example, if DNA has a sequence: 5'-TGACCCCCCC-3' then RNA polymerase will synthesize complementary (5' to 3') to make 5'GGGGGGGUCA-3'. The ribosome will read the mRNA in the 5' to 3'. However, "UCA" in the mRNA strand doesn't code for a stop codon.
In other words, how does the 5'-TGA-3' from mRNA become 5'-UGA-3' stop codon in mRNA.
Consequently, the DNA is supposed to then have in its sequence 5'-TAA/TGA/TAG-3', which corresponds to stop codons.
However, I'm getting slightly confused how this sequence goes from DNA to mRNA.
For example, if DNA has a sequence: 5'-TGACCCCCCC-3' then RNA polymerase will synthesize complementary (5' to 3') to make 5'GGGGGGGUCA-3'. The ribosome will read the mRNA in the 5' to 3'. However, "UCA" in the mRNA strand doesn't code for a stop codon.
In other words, how does the 5'-TGA-3' from mRNA become 5'-UGA-3' stop codon in mRNA.