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A6project

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A painting which is 4 feet wide and 5 feet
long is surrounded by a rectangular frame
6-inches wide. What percent of the area of
the picture and the frame is occupied by
the frame?
 
A painting which is 4 feet wide and 5 feet
long is surrounded by a rectangular frame
6-inches wide. What percent of the area of
the picture and the frame is occupied by
the frame?

Area of painting = 4X5 = 20 feet squared

Area of frame = [area of frame on the edges] + [corners area]
Area of frame = [0.5(4) + 0.5(4) + 0.5(5) + 0.5(5)] + [ 4(0.5)(0.5)]
Area of frame = 10 squared feet

Total area = 20+10 = 30 squared feet

Percentage area of frame = 10/30 = 33.33%
 
Area of painting = 4X5 = 20 feet squared

Area of frame = [area of frame on the edges] + [corners area]
Area of frame = [0.5(4) + 0.5(4) + 0.5(5) + 0.5(5)] + [ 4(0.5)(0.5)]
Area of frame = 10 squared feet

Total area = 20+10 = 30 squared feet

Percentage area of frame = 10/30 = 33.33%


Ohhhh I seeee!
I forgot to add four corners of the frame. Thanks!
 
could some give a detailed explanation as to how the frame area is calculated?

where do you get 0.5 from??
 
Painting = 5 X 4 = 20 feet
Total including frame = (5 + .5 X 2)(4 + .5 X 2) = 6 X 5 = 30
Frame = 30 - 20 = 10
So finally, =10/30*100= 33.33%

I just thought that it would be more time efficient to subtract the painting from the total area to find the are of the frame.
 
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