Hello,
This is a question on AAMC CBT 9, BS passage 6
According to the passage, Peptide A (@ 25 ng/mL) binds to a receptor on cell membranes and promotes a constant secretion of osteoblatin. Peptide B is a competitive inhibitor of Peptide A.
131. When osteoblasts (OB) are incubated with a constant concentration of peptide A (25 ng/mL) and increasing concentrations of B, osteoblatin concentration:
a) increases exponentially
b) increases linearly
c) remains the same
d) decreases
The question asks the examinee to identify the relationship between the osteoblatin concentration and the increasing concentrations of peptide B when osteoblasting are incubated with a constant concentration of peptide A. Peptide A stimulates the production of the osteoblatin, but peptide B does not. Furthermore, Peptide B competitively inhibits Peptide A by binding to the same receptor sites on the cell membranes. As the concentration of the peptide B increases, more and more receptor sites are occupied by the peptide B rather than by Peptide A. This prevents peptide A from being able to activate expression of osteoblatin, therefore decreasing the osteoblatin concentration (D). A, B, C are incorrect becuase the osteoblatin concentration does not increase exponentially (A), increasing linearly (B), or remain constant (C). Thus, D is the best answer.
Why does the osteoblatin concentration decrease? Wouldn't the osteoblatin already made (before B was added) just stay the same? The passage says nothing about osteoblatin disappearing on its own and Peptide B doesnt affect osteoblatin directly in anyway
Can someone plz explain? 0.o
Thanks