Question 53 asks:
An object is placed upright on the axis of a thin convex lens at a distance of four local lengths (4 f) from the center of the lens. An inverted image appears at a distance of 4/3 f on the other side of the lens. What is the ratio of the height of the image to the height of the object.
A) 1/3
B) 3/4
C) 4/3
D) 3/1
So, I know that the thin lens equations tell me
1/f = 1/di + 1/do
1/f = 1/4 + 1/(4/3)
1/f = 1/4 + 3/4
1/f = 1.
And it not even an answer!
The credited answer is A, 1/3.How did i screw up such a simple equation so badly?!
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One of the problems required that i know how to derive the cross sectional area of an artery (pipe) from the diameter. I later learned it was pi/4 * d^2. No MCAT book i have used to this point had let me know i would need to memorize this equation. Are there other, similar, equations, i should memorize?
An object is placed upright on the axis of a thin convex lens at a distance of four local lengths (4 f) from the center of the lens. An inverted image appears at a distance of 4/3 f on the other side of the lens. What is the ratio of the height of the image to the height of the object.
A) 1/3
B) 3/4
C) 4/3
D) 3/1
So, I know that the thin lens equations tell me
1/f = 1/di + 1/do
1/f = 1/4 + 1/(4/3)
1/f = 1/4 + 3/4
1/f = 1.
And it not even an answer!
The credited answer is A, 1/3.How did i screw up such a simple equation so badly?!
----------------------------------------------------------
One of the problems required that i know how to derive the cross sectional area of an artery (pipe) from the diameter. I later learned it was pi/4 * d^2. No MCAT book i have used to this point had let me know i would need to memorize this equation. Are there other, similar, equations, i should memorize?
