Acid-Base question

[kozmik]

Advertisement - Members don't see this ad

A 6 Volt lead storage battery contains 700g of pure H2SO4(l) dissolved in water. The battery is accidentally dropped, spilling its contents. To neutralize the acid, solid sodium carbonate, Na2CO3, is used. Harmless Na2SO4 is formed and CO2 gas is released. (GMW of Na2CO2 is 106g, H2SO4 is 98g, and Na2SO4 is 142 g). If a 2.0M solution of sodium carbonate was used to neutralize the spilled acid, how many litres are needed?

 

[DDS2012]

is the answer 7 L?

 

[doc toothache]

A 6 Volt lead storage battery contains 700g of pure H2SO4(l) dissolved in water. The battery is accidentally dropped, spilling its contents. To neutralize the acid, solid sodium carbonate, Na2CO3, is used. Harmless Na2SO4 is formed and CO2 gas is released. (GMW of Na2CO2 is 106g, H2SO4 is 98g, and Na2SO4 is 142 g). If a 2.0M solution of sodium carbonate was used to neutralize the spilled acid, how many litres are needed?

H2SO4 + Na2CO3=Na2SO4 + H2CO3
700g of H2SO4=7.14 moles
need 7.14 moles of Na2CO3 or 3.57 L of 2.0 M solution

 

[kozmik]

H2SO4 + Na2CO3=Na2SO4 + H2CO3
700g of H2SO4=7.14 moles
need 7.14 moles of Na2CO3 or 3.57 L of 2.0 M solution

I got that answer to, and it's the right numerical answer. however, the answer given is in the form of: 1Lx(757g/212g) 😱
that equals 3.57, but like you I got it by another method

 

[doc toothache]

I got that answer to, and it's the right numerical answer. however, the answer given is in the form of: 1Lx(757g/212g) 😱
that equals 3.57, but like you I got it by another method

757= 7.14x 106
212 = 106 x 2 (2 moles of Na2CO3/liter)