Another organic question..

Started by Avery07
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Avery07

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From Ochem Odyssey:

Which halogen has the most endothermic first propagation step during alkane halogenation?

A) Cl2
B) I2
C) Br2
D) F2
E) At2


Romano says that the answer is B and justifies his answer with the following halogen reactivity with alkanes:

F2 > Cl2 > Br2 > I2

He stops there.. not going on to include At2 and doesn't bother saying why. I can only assume that At2 should be next in this series but evidently not??

Anyone know what's going on here?
 
My guess would be that since homolytic cleavage of the alkane C-H bond takes about 100 kcal/mol, and the formation of the I-H bond (first propagation step) releases about 71, that means that the propagation step has a net of +29 kcal/mol. The Br-H bond on the other hand releases about 88 kcal/mol making the net propagation step +12 kcal/mol. +29 is more endothermic than +12.
 
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