I tried this question from the MCATQuestionaday website:
Q: The Arrhenius equation, shown below, is a description of the relationship between the rate constant, k, the activation energy of the reaction, and the temperature in Kelvin.
k = Ae^-Ea/RT
Here, A and R are constants. If the constant R were half of its actual value, what would happen to the rate constant k? Note: assume the value of e is 2.71.
A It would increase by less than double.
B It would increase by more than double.
C It would decrease to less than half of its current value.
D It would decrease to more than half of its current value.
Why? Since we are concerned primarily with what is happening to R in the reaction, we can ignore the remaining variables and notice that if R doubles, then the value of -EA/RT is being halved. Thus the question comes down to what happens when we have e-1/2, or, expressed another way, 1/√e. Given the value of e as 2.71, we can estimate its square root to be roughly 1.6 (note that 1.52 = 2.25 and 1.72 = 2.89. The inverse of 1.6 is roughly 0.6 meaning the value of the rate constant would decrease but would remain greater than half its current value, making (D) the correct answer.
I am confused since the question is saying what if R becomes half. I thought that if R is halved, then the exponent on e is doubled (because R is in the denominator of the exponent) and k would increase by more than double.
Can someone explain this please?
Q: The Arrhenius equation, shown below, is a description of the relationship between the rate constant, k, the activation energy of the reaction, and the temperature in Kelvin.
k = Ae^-Ea/RT
Here, A and R are constants. If the constant R were half of its actual value, what would happen to the rate constant k? Note: assume the value of e is 2.71.
A It would increase by less than double.
B It would increase by more than double.
C It would decrease to less than half of its current value.
D It would decrease to more than half of its current value.
Why? Since we are concerned primarily with what is happening to R in the reaction, we can ignore the remaining variables and notice that if R doubles, then the value of -EA/RT is being halved. Thus the question comes down to what happens when we have e-1/2, or, expressed another way, 1/√e. Given the value of e as 2.71, we can estimate its square root to be roughly 1.6 (note that 1.52 = 2.25 and 1.72 = 2.89. The inverse of 1.6 is roughly 0.6 meaning the value of the rate constant would decrease but would remain greater than half its current value, making (D) the correct answer.
I am confused since the question is saying what if R becomes half. I thought that if R is halved, then the exponent on e is doubled (because R is in the denominator of the exponent) and k would increase by more than double.
Can someone explain this please?