Hello, this is from the old TBR "metabolic pathways"
Book II, passage #1 (p. 229, answers on p. 257).
I thought I understood the e-transport chain and ox. phosphorylation, but maybe not 100%.
Question 2. You have this drug/poison thing that ultimately binds to ATPsynthase to deactivate it. Okay, thats easy.
What I thought was that the electron transport chain is coupled to the work the ATP synthase (ADP and Pi --> ATP generator). As in, the ETC requires the final e acceptor to be an oxygen (to ensure that it works, to ensure that each complex can successively be reduced, to allow for e- carriers to be oxidized etc. etc.). It is this last part that can make it stop working, and NOT the ATP synthase membrane protein thing that can make it stop working...?
So how does ATP synthase disruption (caused by this drug) lead to "the proton gradient formed by electron transport and proton pumping can no longer be relieved."
And thus "the result is that cells ever to anaerobic metabolism" (instead of proceeding to Krebs/ETC, they go off and make lactate after glycolysis) <-- this logic I get. I do not get the stuff in gray.
(Answers on p.257 - question 2, answer choice C).
Thank you everyone.
Book II, passage #1 (p. 229, answers on p. 257).
I thought I understood the e-transport chain and ox. phosphorylation, but maybe not 100%.
Question 2. You have this drug/poison thing that ultimately binds to ATPsynthase to deactivate it. Okay, thats easy.
What I thought was that the electron transport chain is coupled to the work the ATP synthase (ADP and Pi --> ATP generator). As in, the ETC requires the final e acceptor to be an oxygen (to ensure that it works, to ensure that each complex can successively be reduced, to allow for e- carriers to be oxidized etc. etc.). It is this last part that can make it stop working, and NOT the ATP synthase membrane protein thing that can make it stop working...?
So how does ATP synthase disruption (caused by this drug) lead to "the proton gradient formed by electron transport and proton pumping can no longer be relieved."
And thus "the result is that cells ever to anaerobic metabolism" (instead of proceeding to Krebs/ETC, they go off and make lactate after glycolysis) <-- this logic I get. I do not get the stuff in gray.
(Answers on p.257 - question 2, answer choice C).
Thank you everyone.