Berkeley Review Physics; Section 1, Passage 1

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ManimalJax

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In the first passage of Section 1 of TBR's Physics book, there is a figure of Galileo tossing stones from the top of a rocket. In the explanation to Q#1, it says that acceleration in the y-direction is minus-g. Why is it minus-g if the rock is going to be increasing its acceleration as it is being thrown from the rocket to the surface? I thought minus-g is used when tossing a projectile upwards and against the force of gravity.

What general rule can I take in regards to determining the sign for "g"?
 
It really doesn't matter what the sign is, as long as you stay consistent throughout whatever problem you are doing. You can do a block-on-inclined-ramp question where you call mg and friction positive, so long as their opposing forces are given negative signs.

I don't have that book, but it would seem that they are calling it -g because the rock is accelerating in the direction opposite the rocket's motion (where the rocket's motion is assumed to be the positive direction).

Positive and negative signs don't correlate to speeding up and slowing down -- they have to do with the direction something is accelerating. Remember that acceleration is a vector -- it has both magnitude and direction components.

If you toss an object up against the force of gravity it is given a negative sign (assuming the up direction is positive) because it is always, throughout its entire trip, accelerating in the direction of earth (this is why it slows down and then comes back down). Gravity is always acting on the object.

Regardless of how you've thrown a rock, the force of gravity (mg) will ALWAYS act in the direction towards the surface of the earth (the ground) which you can arbitrarily assign a sign to, as long as you stay consistent.
 
The rocket in the figure is stationary and is resting on the surface of the earth. The man is standing on top of the rocket (that has a height of 20-meters) and he is throwing the stone down.

Could acceleration in the y-direction be negative because the initial height is considered to be 0, and so the rock is falling to a position minus-20 meters?
 
What are the choices?

If using the standard convention (Up is positive, down is negative) then yes, it should be -g because the force of gravity is acting on the pulling it towards the ground. But they'd have to give you some indication what they are calling positive and negative, unless the other choices are nonsensical.
 
Well, the question asks: If two stones, A and B, are thrown from the rocket, which one will stay in the air longer?

The pull of gravity is 9.8 m/s^2, stone A is thrown with an initial velocity of 10 m/s, and stone B is thrown with an initial velocity of 5 m/s.

I am still confused. When I have done projectile motion problems before, particularly ones that involve an object being thrown in a parabolic fashion, I always used minus-g for the first half of the trip (before the projectile reaces its maximum heaight) and positive-g for its trip downward.

I tried to assume the same thing here, that the rock being thrown from the rocket is just basically the second-half of a full parabolic toss, and so g would be positive, but I guess I'm wrong.

The correct answer is that both stones remain in flight for the same amount of time.
 
Yes, if those initial velocities are completely horizontal then they should hit the ground at the same time.

If you shoot a bullet at the same instant that you drop a bullet from the same height they will both hit the ground at the same time. When you shoot a bullet, it's not like it waits until its initial horizontal velocity slows down for it to start falling toward earth (contrary to Wile E. Coyote physics).

Both bullets start accelerating towards the ground the instant they are shot/let go of. And since both have zero initial velocity (in the Y-direction -- the same direction that gravity is acting) they both will hit the ground at the same time. The fact that they have different velocities in the x-direction is completely irrelevant for figuring out how long they are in the air for.
 
MBHockey,

Thanks for the tips. However, I am still confused over when to make g positive or negative.

In the scenario presented in my original post, the passage is describing a projectile that is traveling downwards. MCAT problems that I have done before have been solved successfully when I would make g positive in this situation. However, the solution is mentioning that g is negative in this case.

I know it all depends on how I look at the problem, but in this particular case, how am I supposed to look at the problem in order to understand that g is negative?
 
No problem...we'll come up with a reasonable explanation here.

Can you list exactly what is given (which numbers)? I'm not sure we've got everything listed here that is in the problem.
 
In the first passage of Section 1 of TBR's Physics book, there is a figure of Galileo tossing stones from the top of a rocket. In the explanation to Q#1, it says that acceleration in the y-direction is minus-g. Why is it minus-g if the rock is going to be increasing its acceleration as it is being thrown from the rocket to the surface? I thought minus-g is used when tossing a projectile upwards and against the force of gravity.

What general rule can I take in regards to determining the sign for "g"?

As MBHockey mentioned, the sign convention is not necessary in many problems, as long as you define two opposite directions with opposite signs.

The question is as follows:

  • Of the two tosses done on Earth, A and B, which one stays in the air longer?
    A. Stone A remains in flight longer.
    B. Stone B remains in flight longer.
    C. Both stones remain in flight for the same amount of time.
    D. The time varies with the radius of the stone.

The difference in the question lies the initial velocity of the two trials. Stone A and Stone B both have masses of 1.0 kg and are thrown horizontally from a height of 20 meters with different initial speeds.

Because time of flight depends on the y-direction and both stones are thrown horizontally (with no y-velocity), we can ignore the x-component of this question. In essence, it would be the same question if both stones were dropped straight down.

Whether we define g as 9.8 m/s2 or -9.8 m/s2, it is the same for both stones. Both stones travel the same distance, experiencing the same g, and having the same initial y-direction speed (0), so they each experience the same y-component and thus hit at the same time.

It's exactly as MBHockey explained it "If you shoot a bullet at the same instant that you drop a bullet from the same height they will both hit the ground at the same time. When you shoot a bullet, it's not like it waits until its initial horizontal velocity slows down for it to start falling toward earth (contrary to Wile E. Coyote physics)." And he brings up a wonderful point that cartoons by Warner Brothers often are sources of faulty physics. However, Hannah Barbera cartoons have not been analyzed for physical realism.

As for your question about the sign of g, let's start with the idea that the flight time needs to be a positive value. That is a must according to our conventions.

The kinematics equation of choice here is deltah = 0.5 atexp2 + vot

deltah = 0.5 atexp2 + vot
deltah = 0.5 atexp2 + 0
(2 x deltah)/g = texp2

From here, it's your choice as to what signs to use. If you say it fell 20 meters, then deltah = -20. In order to have the time be a positive value (and for square roots to be real), we need to use -9.8 m/s2 for g. The math tells is that the flight time when dropped or thrown horizontally from a height of 20 meters is square root of 4 (square root of 40/10), or about 2 seconds for any object in the absence of wind resistance.
 
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