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The DNA of a bacteria is labeled with a radioactive phosphate. Following mitosis, each daughter cell will have:
A. 1/4 the radioactivity of the parent
B. 1/2 the radioactivity of the parent
C. The same radioactivity as the parent
D. 2 times the radioactivity as the parent
E. It is not possible to determine
I was stuck on either choice B and C, but I chose C and got it wrong.
The right answer is B, and their explanation is something to do with semiconservative replication which I understand, but don't bacteria use asexual reproduction and therefore have the exact DNA structure of their parent?
A. 1/4 the radioactivity of the parent
B. 1/2 the radioactivity of the parent
C. The same radioactivity as the parent
D. 2 times the radioactivity as the parent
E. It is not possible to determine
I was stuck on either choice B and C, but I chose C and got it wrong.
The right answer is B, and their explanation is something to do with semiconservative replication which I understand, but don't bacteria use asexual reproduction and therefore have the exact DNA structure of their parent?