Biochem Question: Where do H+ come from in Lactic Acidosis?

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pizza100

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Hi everyone.

During heavy exercise, muscles get additional energy by converting glucose to pyruvate in glycolysis. The pyruvate then gets converted to lactate (the anion form of lactic acid) to free up the NAD+ for the next cycle of glycolysis.

I don't understand where additional H+ come from that would lower the blood pH and cause Acidosis? The process above produces lactate, not lactic acid.

Please help clarify this.
 
At physiologic pH lactic acid loses its proton and becomes lactate.
 
pKA for lactic acid is 3.86 so at physiological pH (pH higher than pKa), majority of lactic acid will exist in its dissociated form (LA --> Lactate + H+)
 
I understand that lactic acid turns into lactate and H+ at physiologic conditions. What I don't understand is where does lactic acid come from? The process of regenerating NAD+ for glycolysis involves turning pyruvate into lactate, NOT lactic acid. Lactate does not have H+ to lower the pH.
 
Hi everyone.

During heavy exercise, muscles get additional energy by converting glucose to pyruvate in glycolysis. The pyruvate then gets converted to lactate (the anion form of lactic acid) to free up the NAD+ for the next cycle of glycolysis.

I don't understand where additional H+ come from that would lower the blood pH and cause Acidosis? The process above produces lactate, not lactic acid.

Please help clarify this.

This is actually a pretty good question. My biochem professor here has a problem with the term "lactic acid acidosis." We had a few slides where he argued that the hydrogen ions are the product of ATP hydrolysis, and that high levels of lactate are only a marker for the acidosis.

He then said that this is a hotly contested topic in biochemistry. I have no idea whether that is true, but his soap-box rant (and power point slides) made sense.
 
I understand that lactic acid turns into lactate and H+ at physiologic conditions. What I don't understand is where does lactic acid come from? The process of regenerating NAD+ for glycolysis involves turning pyruvate into lactate, NOT lactic acid. Lactate does not have H+ to lower the pH.

Exactly, and the lactate dehydrogenase enzyme actually consumes a proton during the reaction from pyruvate to lactate.
 
Thanks for the reply, Renaissance Man. Wikipedia says many sources disagree to where the H+ come from.

Can we at least confirm that excess glycolysis and production of lactate does produce H+ and lower the blood pH? I wonder the term "acidosis" is actually a decrease in blood pH at all?
 
Thanks for the reply, Renaissance Man. Wikipedia says many sources disagree to where the H+ come from.

Can we at least confirm that excess glycolysis and production of lactate does produce H+ and lower the blood pH? I wonder the term "acidosis" is actually a decrease in blood pH at all?


Yes i believe that is correct. The H+ is there the dispute is just over where its coming from. The acidosis is a decrease in blood pH.
 
I said my bad son. I didnt get what he was asking at first. Should have read the whole ques.

I was just joking around man, I must have been typing it up while you replied. Should've made my sarcasm more apparent.

Anyways, yes blood pH does definitely decrease, and levels of lactate are a reliable marker of acidosis.
 
Hi everyone.

During heavy exercise, muscles get additional energy by converting glucose to pyruvate in glycolysis. The pyruvate then gets converted to lactate (the anion form of lactic acid) to free up the NAD+ for the next cycle of glycolysis.

I don't understand where additional H+ come from that would lower the blood pH and cause Acidosis? The process above produces lactate, not lactic acid.

Please help clarify this.

Water.... there is always water in the system to provide protons. Biologists have a bad habit of not balancing protons for aqueous equations.


I wonder what the pka of nad+ is. Someone look up the reduction reaction using nadh I bet there are unaccounted for waters and hydrogens in there
 
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Water.... there is always water in the system to provide protons. Biologists have a bad habit of not balancing protons for aqueous equations.


I wonder what the pka of nad+ is. Someone look up the reduction reaction using nadh I bet there are unaccounted for waters and hydrogens in there

Water in the system can provide protons to molecules but that wouldn't change the pH of the solution.
 
Water in the system can provide protons to molecules but that wouldn't change the pH of the solution.

It can. Technically speaking water is the only thing that ever alters the pH as H+ is the strongest acid that is allowed to exist in aqueous solution. As weak acids are usually base salt derivatives (conjugates), what you often do is put in a species which partially associates with OH- resulting in an increase in [H+] with no H+ ever actually introduced to the system.

I haven't looked up the total reaction yet, but if weak basic salts are involved they will suck hydroxide out of the mix leaving hydrogen. H+ and OH- are pretty stabile ions in water. With the exception of the normal organic functional groups most things react pretty strongly to make sure they have a neutral charge. It isn't always about producing protons. Sometimes producing species which sequester OH works fine as well.

NADH loses a hydrogen and goes to NAD+ rather than NAD-. This isn't a normal disassociation reaction, 2 e- are missing. I'd have to think about it for a bit but I would suspect either a water is being utilized in this reaction or nad sequesters OH itself. Not really sure on those points, but such things are pretty common and pH likes to do counterintuitive things in electrochem. If you had that course you may remember that you can often balance an equation by atoms but the electrons will be all messed up. I remember being frustrated often in biochem because of this.
 
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It can. Technically speaking water is the only thing that ever alters the pH as H+ is the strongest acid that is allowed to exist in aqueous solution. As weak acids are usually base salt derivatives (conjugates), what you often do is put in a species which partially associates with OH- resulting in an increase in [H+] with no H+ ever actually introduced to the system.

I haven't looked up the total reaction yet, but if weak basic salts are involved they will suck hydroxide out of the mix leaving hydrogen. H+ and OH- are pretty stabile ions in water. With the exception of the normal organic functional groups most things react pretty strongly to make sure they have a neutral charge. It isn't always about producing protons. Sometimes producing species which sequester OH works fine as well.

NADH loses a hydrogen and goes to NAD+ rather than NAD-. This isn't a normal disassociation reaction, 2 e- are missing. I'd have to think about it for a bit but I would suspect either a water is being utilized in this reaction or nad sequesters OH itself. Not really sure on those points, but such things are pretty common and pH likes to do counterintuitive things in electrochem. If you had that course you may remember that you can often balance an equation by atoms but the electrons will be all messed up. I remember being frustrated often in biochem because of this.

There's a difference between saying that something takes out OH- and saying that water is providing additional protons. In this example, water isn't providing additional protons to produce acidosis and a proton is actually incorporated into pyruvate to form lactate. But as you exercise, you produce more CO2 which becomes carbonic acid in the blood.
 
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There's a difference between saying that something takes out OH- and saying that water is providing additional protons. In this example, water isn't providing additional protons to produce acidosis.

Yes it is.... Removal of OH leaves behind an H. That was water's H and now it is an H lowering the pH. Disassociation of water by whatever means is chemically I distinct from any other acidic disassociation. Whether water comes in and pulls apart HCl or something else comes in to pull out OH the net result is an increase in proton concentration relative to OH and that is all that matters for pH


But if you don't want to think of it that way or semantically disagree.... Whatever. The point I was making is that water is not always balanced in biochemical reactions and the most likely guy to appear unaccounted for is usually the proton.
 
Please explain to me how pulling out OHs or mentioning HCl has anything to do with lactic acidosis.
 
Please explain to me how pulling out OHs or mentioning HCl has anything to do with lactic acidosis.

Did you read anything else I posted? I don't know that this is exactly what happens. Just a hunch. The last post was only in response to you saying water cannot provide protons to lower pH. It absolutely can. Any time you dissolve weak conjugate acid or base salts it is the water that provides the proton or hydroxide to alter pH. This happens via sequestration of the other. If you don't like the word "provides".... Whatever. That is semantic.

When pyruvate is fermented to lactate, an NADH is consumed and turned to NAD+. In my experience with redox reactions, very often water is involved and a proton is either liberated or consumed. If you haven't noticed this you probably haven't had enough chem majors in your class. We tend to freak out when the bio guys just start throwing protons around all willie nillie.

If you look here: http://en.wikipedia.org/wiki/Nicotinamide_adenine_dinucleotide

It looks like 2 hydrogens are involved in this reaction. One, a proton, is released to solution. The other is involved in redox. This is the first possibility I mentioned stating I wasn't sure and didn't really want to deal with looking it up now :prof:

The other possibility I mentioned (I think explicitly) was OH sequestration somewhere in the redox. That looks false for this case, but it does happen.
 
Not to slam the intellectual theory and biochem that is going on ITT, but is knowing the answer to this very minute question going to change anything in your life?
 
Not to slam the intellectual theory and biochem that is going on ITT, but is knowing the answer to this very minute question going to change anything in your life?

In digging up the answer I got a better understanding of that process :shrug: it will be easier to recall in the future.
 
This thread will be all I study for Step 1 biochem 👍
 
ajpregu.physiology.org/content/287/3/R502.full.pdf

All the answer you are looking for can be found here.

It's kind of sad that many of our professors do not think critically enough to challenge these less-than-robust interpretation of experiments from decades ago, and keep on teaching us the wrong ideas.

Another example of this I noticed is how they cite increased 2,3-BPG production for a right shift in high-altitude hypoxia is considered a compensatory mechanism to facilitate oxygen delivery to muscles, when it's is blatantly obvious that a LEFT shifted curve would be protective against this kind of hypoxia (as easily shown by how much longer neonatal mice can survive compared to adult mice because they have high levels of fetal hemoglobin in a CO2 chamber, and also by how every species or human adapted to high altitude have left shifted HD curves).
 
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ATP Hydrolysis causes the lowering of pH (a free proton is released). It just happens that at times of intense energy usage lactate also builds up.

Normally this feeds the H gradient which powers the ATPase. It would help to produce more ATP and would be self limiting in terms of proton production. If you blocked the ATPase function it may get you there but I don't think that is what happens in acidosis.
 
Did you read anything else I posted? I don't know that this is exactly what happens. Just a hunch. The last post was only in response to you saying water cannot provide protons to lower pH. It absolutely can. Any time you dissolve weak conjugate acid or base salts it is the water that provides the proton or hydroxide to alter pH. This happens via sequestration of the other. If you don't like the word "provides".... Whatever. That is semantic.

When pyruvate is fermented to lactate, an NADH is consumed and turned to NAD+. In my experience with redox reactions, very often water is involved and a proton is either liberated or consumed. If you haven't noticed this you probably haven't had enough chem majors in your class. We tend to freak out when the bio guys just start throwing protons around all willie nillie.

If you look here: http://en.wikipedia.org/wiki/Nicotinamide_adenine_dinucleotide

It looks like 2 hydrogens are involved in this reaction. One, a proton, is released to solution. The other is involved in redox. This is the first possibility I mentioned stating I wasn't sure and didn't really want to deal with looking it up now :prof:

The other possibility I mentioned (I think explicitly) was OH sequestration somewhere in the redox. That looks false for this case, but it does happen.

Actually.... I have this backwards..... I hate NADH.


I think.... Dammit....

Yeah I had this backwards. A proton is consumed when NADH is formed. ATP has to be the source
 
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Actually.... I have this backwards..... I hate NADH.


I think.... Dammit....

Yeah I had this backwards. A proton is consumed when NADH is formed. ATP has to be the source

Pretty sure a proton is consumed when NAD+ is formed from NADH, not the other way around.

Think about it in terms of balancing the charge:
NADH + H+ <-> NAD+ + H2 (+1 charge on either side, since NAD+ is +1, H+ has to be on the other side of the equation, or else it's going to be 0 on one side and +2 on the other)

I don't think you actually form a hydrogen gas molecule at physiological conditions, but at least you can think about it this way. Wikipedia denotes H+ and 2e-, which is confusing - that's a hydride ion, not a proton.

The balanced equation can be seen as:
NADH = NAD+ + H-
Pyruvate = C3H3O3-
Lactate = C3H5O3- = Pyruvate + H2

C3H3O3- [Pyruvate] + (NAD+ + H-) [NADH] + H3O+ <-----> C3H5O3- [Lactate] + NAD+ + H2O

Which clearly shows that lactate formation actually compensates for the underlying metabolic acidosis by taking up a proton.

This also interesting because in metabolic acidosis, according to the Le Chatelier's principle, you would be driving the equilibrium to the right because of the surplus of H+, and therefore increase lactate formation.

Again, one of the sources of H+ from the metabolic acidosis is from ATP hydrolysis as someone pointed out. You can read about this in this review: ajpregu.physiology.org/content/287/3/R502.full.pdf
 
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Pretty sure a proton is consumed when NAD+ is formed from NADH, not the other way around.

Think about it in terms of balancing the charge:
NADH + H+ NAD+ + H2 (+1 charge on either side, since NAD+ is +1, H+ has to be on the other side of the equation, or else it's going to be 0 on one side and +2 on the other)

I don't think you actually form a hydrogen gas molecule at physiological conditions, but at least you can think about it this way. Wikipedia denotes H+ and 2e-, which is confusing - that's a hydride ion, not a proton.

The balanced equation can be seen as:
NADH = NAD+ + H-
Pyruvate = C3H3O3-
Lactate = C3H5O3- = Pyruvate + H2

C3H3O3- [Pyruvate] + (NAD+ + H-) [NADH] + H3O+ C3H5O3- [Lactate] + NAD+ + H2O

Which clearly shows that lactate formation actually compensates for the underlying metabolic acidosis by taking up a proton.

This also interesting because in metabolic acidosis, according to the Le Chatelier's principle, you would be driving the equilibrium to the right because of the surplus of H+, and therefore increase lactate formation.

Again, one of the sources of H+ from the metabolic acidosis is from ATP hydrolysis as someone pointed out. You can read about this in this review: ajpregu.physiology.org/content/287/3/R502.full.pdf

I didn't say a hydrogen gas molecule was formed.

As for the rest of it... I'll look it back over. The correct answer is the opposite of what I said in the post I quoted. If I said it wrong that was a typo .
 
In digging up the answer I got a better understanding of that process :shrug: it will be easier to recall in the future.

Hmm, okay. But is any of this going to matter, even for Step 1? Obviously once Step 1 is done this is all out the window, correct? I'm past Step 1 and thus I guess I don't really care anymore. Also guilty of not being a chemistry major.


Anyways, not trying to de-rail the thread, so ignore my ramblings and continue on with this intellectual discussion. Despite how much I may seem like I'm being annoyed by it, I am continuing to read every reply.
 
Hmm, okay. But is any of this going to matter, even for Step 1? Obviously once Step 1 is done this is all out the window, correct? I'm past Step 1 and thus I guess I don't really care anymore. Also guilty of not being a chemistry major.


Anyways, not trying to de-rail the thread, so ignore my ramblings and continue on with this intellectual discussion. Despite how much I may seem like I'm being annoyed by it, I am continuing to read every reply.

um.... depends. If you are a list memorizer and that actually works for you probably not.

Personally I couldn't memorize my way out of a cardboard box... or like... something where memorization would be of greater utility 😕
So when I look up those little nitty gritty details I am not left just imagining that little magic gnomes make it happen. even if I don't remember all the details I know about how things fit together so it helps me with application questions which I would argue would be pretty helpful on step1. Havent taken it yet, but have taken plenty of practice questions and we have a few profs who write for it as well.
 
Hmm, okay. But is any of this going to matter, even for Step 1? Obviously once Step 1 is done this is all out the window, correct? I'm past Step 1 and thus I guess I don't really care anymore. Also guilty of not being a chemistry major.


Anyways, not trying to de-rail the thread, so ignore my ramblings and continue on with this intellectual discussion. Despite how much I may seem like I'm being annoyed by it, I am continuing to read every reply.

As far as the actual detail about where the proton came from? You probably won't see that anytime during your lifetime ever again. However, the information isn't what's important here - it's the thought process.

It's important to be able to look at what they are teaching us - lactic acidosis results from lactate formation - and actually critically think about whether that's actually true. This thinking process is what's going to distinguish a great physician from a mediocre one, not the knowledge of specifically where the proton came from - you can look up information, but not way of thinking.
 
Hi everyone.

During heavy exercise, muscles get additional energy by converting glucose to pyruvate in glycolysis. The pyruvate then gets converted to lactate (the anion form of lactic acid) to free up the NAD+ for the next cycle of glycolysis.

I don't understand where additional H+ come from that would lower the blood pH and cause Acidosis? The process above produces lactate, not lactic acid.

Please help clarify this.

Think about why it's making glucose. Muscle needs energy, but has low O2, so it's going to produce lactate using LDH which converts NADH + H to NAD. Lactate is transported to the liver through the Cori cycle. Liver LDH converts lactate to pyruvate thus producing NADH + H. This hydrogen produced in the liver is what causes your pH levels to increase (lower pH value). The end result is that pyruvate can go through gluconeogenesis and supply more glucose to the muscle. Since your liver is not using excessive amounts of oxygen, NADH can go through the electron transport chain to make massive amounts of ATP. Massive ATP hydrolysis also increases pH levels.

ajpregu.physiology.org/content/287/3/R502.full.pdf

All the answer you are looking for can be found here.

It's kind of sad that many of our professors do not think critically enough to challenge these less-than-robust interpretation of experiments from decades ago, and keep on teaching us the wrong ideas.

Another example of this I noticed is how they cite increased 2,3-BPG production for a right shift in high-altitude hypoxia is considered a compensatory mechanism to facilitate oxygen delivery to muscles, when it's is blatantly obvious that a LEFT shifted curve would be protective against this kind of hypoxia (as easily shown by how much longer neonatal mice can survive compared to adult mice because they have high levels of fetal hemoglobin in a CO2 chamber, and also by how every species or human adapted to high altitude have left shifted HD curves).

I'm amused by the irony about thinking critically and about how you say it makes one a great physician if they can reason. You made me think critically and argue with my own reasoning so I must thank you.

2,3 BPG(negatively charged) stabilizes deoxyHB by binding to HIS residues(positively charged) on the B chain. Favoring the deoxy state(or stabilizing HB) releases oxygen thus increasing p50(it's like Km...lower=more tightly bound, higher=less tightly bound) and results in a right shift.

A left shifted curve decreases p50, so your Hb will hold onto oxygen more tightly (higher saturation of Hb) when your partial pressure of oxygen is lower. When you have no air in the atmosphere (low partial pressure) or metabolically active tissue, you do not want Hb to have a left shift. You'd have decreased unloading which is why people don't feel too hot when they first arrive at a high altitude location. BPG is increased in response to low O2. High CO2 or low pH has the same result but acts through a different mechanism.

Fetal Hb gamma is left shifted, think lower p50 and higher Hb saturation (at all levels), because it's competing with maternal Hb A so it needs to be able to grab more oxygen from maternal circulation. In this case, it can simply grab more oxygen out of it's high CO2 chamber. Adult mice have to adapt which takes longer while Hb gamma is already produced with a low p50 or high affinity for oxygen.
 
Think about why it's making glucose. Muscle needs energy, but has low O2, so it's going to produce lactate using LDH which converts NADH + H to NAD. Lactate is transported to the liver through the Cori cycle. Liver LDH converts lactate to pyruvate thus producing NADH + H. This hydrogen produced in the liver is what causes your pH levels to increase (lower pH value). The end result is that pyruvate can go through gluconeogenesis and supply more glucose to the muscle. Since your liver is not using excessive amounts of oxygen, NADH can go through the electron transport chain to make massive amounts of ATP. Massive ATP hydrolysis also increases pH levels.
Regardless of the balanced equation (and I believe you have it correct there), you are describing a cyclic process. For every NAD produced in the tissue a proton is consumed, for every one liberated in the liver one is produced. The net change is 0. Also, "pH unit" is not really a unit of measurement. "increased pH unit" doesnt mean lower pH. Increased [H+] means lower pH, the unit of which IS pH. i.e. "increase pH levels" isn't really a thing. Your "pH" is a measurement of your hydrogen ion levels.

All in all, the only explanation that I have seen that makes good chemical sense is just the massive H+ release from ATP hydrolysis which overwhelms the ability for mitochondria to use in ATP production. The H+ leeches into the surrounding tissue (via whatever method of membrane transport you prefer, it doesn't really matter which, there are a few which can handle shuttling of hydrogen ions). Normally (and I am guessing here, but it makes sense) the H+ production from normal ATP hydrolysis would be offset by CO2 production in ox-phos resulting in no net pH change.
 
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Regardless of the balanced equation (and I believe you have it correct there), you are describing a cyclic process. For every NAD produced in the tissue a proton is consumed, for every one liberated in the liver one is produced. The net change is 0. Also, "pH unit" is not really a unit of measurement. "increased pH unit" doesnt mean lower pH. Increased [H+] means lower pH, the unit of which IS pH. i.e. "increase pH levels" isn't really a thing. Your "pH" is a measurement of your hydrogen ion levels.

Good point,it is 1 to 1. The key then is transferring lactate to the liver. That produces the NADH necessary to feed into ATP hydrolysis which is the source of the hydrogen as everyone else is saying. I believe excessive CO2 production in the muscle also contributes to increasing [H+] or lowering pH.

Edit: That goes along with what you're saying. The excess CO2 in ox-phos should cause plasma CO2 levels to rise. This causes H+ to be liberated from Hb and HCO-. This would favor more O2 unloading.
 
A left shifted curve decreases p50, so your Hb will hold onto oxygen more tightly (higher saturation of Hb) when your partial pressure of oxygen is lower. When you have no air in the atmosphere (low partial pressure) or metabolically active tissue, you do not want Hb to have a left shift. You'd have decreased unloading which is why people don't feel too hot when they first arrive at a high altitude location. BPG is increased in response to low O2. High CO2 or low pH has the same result but acts through a different mechanism.

Fetal Hb gamma is left shifted, think lower p50 and higher Hb saturation (at all levels), because it's competing with maternal Hb A so it needs to be able to grab more oxygen from maternal circulation. In this case, it can simply grab more oxygen out of it's high CO2 chamber. Adult mice have to adapt which takes longer while Hb gamma is already produced with a low p50 or high affinity for oxygen.

I agree with most of this except the consequences of decreased atmospheric pressure. (did you mean no oxygen in the air? or did you really mean "no air in the air"? 😕)

A left shift makes the blood more able to carry O2 in lower pO2 conditions. If you had Hb that was stuck at "normal", and then went to high atmosphere where pO2 is lower, your blood leaves the lungs at lower saturation following directly with this curve
MbHbBndCrv.GIF


If your normal pO2 is 50-60torr you will usually experience 80-90% saturation (i'm just throwing numbers out based on the graph, not intended to be real numbers by any means). However if you go to a place, or if I ventilate you with a mixture that has only half this oxygen content, ~25torr, now your blood only leaves with 50% of its oxygen AND will be more likely to dump its oxygen inappropriately due to the cooperative binding effect of Hb. A left shift in the binding curve, in this situation, would result in 25torr sitting nearer to the top of the curve. Lower p50 means that a pO2 lower than 26 (the number in the graph) will be the new p50, so at 26 more than 50% of Hb will be bound.
 
Good point,it is 1 to 1. The key then is transferring lactate to the liver. That produces the NADH necessary to feed into ATP hydrolysis which is the source of the hydrogen as everyone else is saying. I believe excessive CO2 production in the muscle also contributes to increasing [H+] or lowering pH.

Edit: That goes along with what you're saying. The excess CO2 in ox-phos should cause plasma CO2 levels to rise. This causes H+ to be liberated from Hb and HCO-. This would favor more O2 unloading.

IIRC, the liver actually has another enzyme that can metabolize lactate. I don't really remember what that is... it was in phys and that was last year and I don't have to know it again for another 8 months or so. You're right that the liver is the primary source for lactate conversion.... I just cant remember exactly if that is because the only place that the enzyme for the reverse reaction is available is the liver (is it reversible? couldnt find it on a quick googling) or if because the tissues it is produced in don't have the proper cofactors (NAD is rapidly consumed in these tissues) or what exactly.....

Here is a good quote from the wiki on this:
The effect of lactate production on acidosis has been the topic of many recent conferences in the field of exercise physiology. Robergs et al. have discussed the creation of H+ ions that occurs during glycolysis.[10] and claim that the idea that acidosis is caused by the production of lactic acid is a myth (a "construct"), pointing out that part of the lowering of pH is due to the reaction ATP-4+H2O=ADP-3+HPO4-2+H+, and that reducing pyruvate to lactate (pyruvate+NADH+H+=lactate+NAD+) actually consumes H+. However, a response by Lindinger et al.[11] has been written claiming that Robergs et alii ignored the causative factors of the increase in concentration of hydrogen ions (denoted [H+]). Specifically, lactate is an anion, and its production causes a reduction in the amount of cations such as Na+ minus anions, and thus causes an increase in [H+] to maintain electroneutrality. Increasing partial pressure of CO2, PCO2, also causes an increase in [H+]. During exercise, the intramuscular lactate concentration and PCO2 increase, causing an increase in [H+], and, thus, a decrease in pH.


The bold part is what I was talking about earlier when i mentioned OH sequestration. I think they have this part wrong if we are being technical.... lactate, an anion, is produced from pyruvate, also an anion (the conjugate base of pyruvic acid) so there is no basis for pH change there.

I don't know how solid that theory is, because you typically want to identify weak acid/base species in order to defend this, but it is readily accepted that the incorporation of non H or OH ions will usually cause a shift in the H/OH ratio to, as mentioned, maintained electroneutrality. It is presented in gen chem and analytical in specific ways, but in solution everyone is flying around in a partial ionized state, sometimes Hs and OHs associate a little stronger with one species over another or with each other and the "rules' we use to describe how this happens are really more tenancies than rules.

All in all, every source of hydrogen, except for ATP, seems to either balance and/or cancel out so... as much as I don't like it, that is where I think I'm landing until I see something different.
 
Think about why it's making glucose. Muscle needs energy, but has low O2, so it's going to produce lactate using LDH which converts NADH + H to NAD. Lactate is transported to the liver through the Cori cycle. Liver LDH converts lactate to pyruvate thus producing NADH + H. This hydrogen produced in the liver is what causes your pH levels to increase (lower pH value). The end result is that pyruvate can go through gluconeogenesis and supply more glucose to the muscle. Since your liver is not using excessive amounts of oxygen, NADH can go through the electron transport chain to make massive amounts of ATP. Massive ATP hydrolysis also increases pH levels.
You are not accounting for the fact that acidosis during strenuous exercise is mostly a muscle tissue specific phenomenon. While your blood pH also decreases, your muscle tissues are going to be at a lower pH than the rest of your body. Your liver pH theory 1) does not show an additional proton being made and therefore how a systemic acidosis came about, and 2) does not address the lower pH for muscles for the localized acidosis either.

Good point,it is 1 to 1. The key then is transferring lactate to the liver. That produces the NADH necessary to feed into ATP hydrolysis which is the source of the hydrogen as everyone else is saying. I believe excessive CO2 production in the muscle also contributes to increasing [H+] or lowering pH.

Edit: That goes along with what you're saying. The excess CO2 in ox-phos should cause plasma CO2 levels to rise. This causes H+ to be liberated from Hb and HCO-. This would favor more O2 unloading.
I do agree that production of CO2 would contribute to the metabolic acidosis in addition to ATP hydrolysis.

I'm amused by the irony about thinking critically and about how you say it makes one a great physician if they can reason. You made me think critically and argue with my own reasoning so I must thank you.

2,3 BPG(negatively charged) stabilizes deoxyHB by binding to HIS residues(positively charged) on the B chain. Favoring the deoxy state(or stabilizing HB) releases oxygen thus increasing p50(it's like Km...lower=more tightly bound, higher=less tightly bound) and results in a right shift.

A left shifted curve decreases p50, so your Hb will hold onto oxygen more tightly (higher saturation of Hb) when your partial pressure of oxygen is lower. When you have no air in the atmosphere (low partial pressure) or metabolically active tissue, you do not want Hb to have a left shift. You'd have decreased unloading which is why people don't feel too hot when they first arrive at a high altitude location. BPG is increased in response to low O2. High CO2 or low pH has the same result but acts through a different mechanism.

Fetal Hb gamma is left shifted, think lower p50 and higher Hb saturation (at all levels), because it's competing with maternal Hb A so it needs to be able to grab more oxygen from maternal circulation. In this case, it can simply grab more oxygen out of it's high CO2 chamber. Adult mice have to adapt which takes longer while Hb gamma is already produced with a low p50 or high affinity for oxygen.
Like my biochem professor, you are simplifying delivery of oxygen to 2 points and a transporter - e.g. lung for pickup and "tissue" for target, and Hb for transporter.

Problem with that is that tissue is not one point in reality, it has a arterial side and a venous side and many points in between. While it is true that right shifted Hb is able to unload at a higher pO2, it is also true that in high altitude hypoxia you do not have enough molecules of Hb bound O2 for all of your tissues.

If you were to unload them earlier on the arterial side of the tissue, your Hb are going to be deoxygenated by the time it reaches the venous side - those tissues are going to die. On the other hand if you have a left shifted Hb, you'd hold onto your O2 until the pO2 dictates the release of O2 from Hb, and therefore as more even distribution of O2 under hypoxic stress. (Think of it as food rationing in famine, rather than handing out the limited amount of food for whoever yells hungry first - everyone is hungry, except in this case you are handing out oxygen.)

This is not even taking into consideration that a right shifted Hb has lower ability to bind O2 in the lungs, so your total supply of O2 is going to be decreased in a state when you have low amounts of O2 to begin with.

2,3-BPG is helpful with the allocation of O2 when availability isn't an issue, but it does not address the problem caused by the lack of availability of O2. You can facilitate the unloading all you want - it still doesn't change the fact that don't have enough to unload in the first place. And in high altitude hypoxia, availability is the problem, not the allocation.

The fetal hemoglobin example proves exactly what I'm saying - if you have a left shifted Hb curve (neonate mice with more fetal Hb), you are going to survive longer. E.g., LEFT shifted curve is protective vs. this kind of hypoxia.

And look under the hemoglobin section in this article:
http://www.ncbi.nlm.nih.gov/pmc/articles/PMC3154690/

And I mean, just think about how ridiculous the oxygen dissociation curve is in the context of oxygen delivery - you are moving oxygen from Hb to Mb - which isn't affected by 2,3-BPG. However, Mb isn't the endpoint, it has to still deliver it to the mitochondria - so it's obvious that the pO2 experienced by the mitochondria is the ultimate driving force for oxygen delivery and not whether there is 2,3-BPG. That's just there to make sure that Hb to Mb isn't the rate limiting step, which in most cases it isn't.

All in all, every source of hydrogen, except for ATP, seems to either balance and/or cancel out so... as much as I don't like it, that is where I think I'm landing until I see something different.
Just a little thing on the side - it's a little confusing to follow along what you write, because you use hydrogen/proton/etc. interchangeably, and we have to try to figure out exactly what you meant by "hydrogen".

It might be easier to follow if you clearly distinguish between:

H+ as proton
H- as hydride
H. as hydrogen radical
H2 as hydrogen (gas)
 
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