- Joined
- Mar 7, 2007
- Messages
- 934
- Reaction score
- 861
In Section 1, Passage 4, Question 27 BR states then when the starting point and ending points are different heights, the projectile's path is not symmetric. Assuming the heights were equal, than a launch angle of 45 degrees would correspond to maximum range. BR then states that when dealing with different heights minimizing the launch angle would maximize the x-direction velocity giving greatest range in the graph.
THEN.... On the next page, Passage 5, Question 30, with three balls each with differenent launch angles and again with a starting and ending heights being different, you're asked the order that they'd hit the ground. Ball 1 is launched horizontally, Ball 2 is launched at 30 degrees, and Ball 3 is launched at 60 degrees. Going off of what I though from the prior question, I thought that the ball launched at 30 degrees would have the greatest range, thus land last. However BR says that the ball with the steepest launch angle (60 degrees/Ball 3) would have the greatest range/strike the ground last.
Can someone help explain the launch angle:range issue I'm having? Thanks so much!
THEN.... On the next page, Passage 5, Question 30, with three balls each with differenent launch angles and again with a starting and ending heights being different, you're asked the order that they'd hit the ground. Ball 1 is launched horizontally, Ball 2 is launched at 30 degrees, and Ball 3 is launched at 60 degrees. Going off of what I though from the prior question, I thought that the ball launched at 30 degrees would have the greatest range, thus land last. However BR says that the ball with the steepest launch angle (60 degrees/Ball 3) would have the greatest range/strike the ground last.
Can someone help explain the launch angle:range issue I'm having? Thanks so much!
