BR question. Confusing~~

chaser0

Full Member
May 10, 2009
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    Solute X does not dissociate once in solution. If another impurity were chosen instead that can dissociate into two particles in solution, how would the freezing point be affected?
    A.) the freezing point will decrease by twice as much as expected, if the impurity does not dissociate.
    B.) the FP would decrease by as much as expected, if the impurity does not dissociate.
    C.) the freezing point would decrease by half as much as expected, if the impurity does not dissociate.
    D.) the FP would be constant.


    Anyone want to give an answer and their reason??
     
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    MedPR

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    1. Pre-Podiatry
      Going with B. FP is a colligative property meaning that only the number of particles matters. If something doesn't dissociate then the vant hoff factor is 1. If something that can dissociate into two things, but doesn't dissociate in the solution given then the van't hoff factor is still 1.
       
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