CALCULATION question

[Music Man]

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A colon lavage prep contains the following mixture of dry powder to prepare 4L of solution:

NaCL 5.84g (Na=23, Cl=35.5)
KCl 2.98g (K=39)
NaHCO3 6.72g (HCO3=61)
NaSO4 22.72g (SO4=96)

Calculate the mEq each of sodium and chloride present per liter of prepared solution.

?

 

[Sparda29]

Eww, I hate these.

 

[charfdorn]

A colon lavage prep contains the following mixture of dry powder to prepare 4L of solution:

NaCL 5.84g (Na=23, Cl=35.5)
KCl 2.98g (K=39)
NaHCO3 6.72g (HCO3=61)
NaSO4 22.72g (SO4=96)

Calculate the mEq each of sodium and chloride present per liter of prepared solution.

?

Oh, your homework? Yeah, we're gonna do that for you.

 

[rxforlife2004]

A colon lavage prep contains the following mixture of dry powder to prepare 4L of solution:

NaCL 5.84g (Na=23, Cl=35.5)
KCl 2.98g (K=39)
NaHCO3 6.72g (HCO3=61)
NaSO4 22.72g (SO4=96)

Calculate the mEq each of sodium and chloride present per liter of prepared solution.

?

freaking easy...and u can't do it? Shame on you...this is such a joke calculation problem!...so freaking easy...

 

[Music Man]

Dang...is it really that easy? It was the last problem in the chapter, I got all the others right. Yeah, I guess I is stupid than.

 

[charfdorn]

Dang...is it really that easy? It was the last problem in the chapter, I got all the others right. Yeah, I guess I is stupid than.

Well, it is just stoichiometry, right? Like, from back in Chem I?

 

[Milly12]

So many responses, yet so little help... This should give you all the answers you need:

http://allnurses.com/general-nursing-student/milliequivalent-formula-question-230718.html

I hate conversions involving mg --> mEq or mmol. Royal PIA

 

[johnconner]

I don't like that formula because you have to memorize something which can lead to a mistake. Just remember to keep your units and you wont have to memorize anything.

Convert to moles then mEq.

g/L * L * mole/g * eq/mole * 1000 mEq/1 eq

 

[npage148]

if you have trouble with mw=g/mol and M=mol/l then i don't know how the rest of pharm school will be for you

 

[aboveliquidice]

Oh, your homework? Yeah, we're gonna do that for you.

NaCL 5.84g (Na=23, Cl=35.5)
KCl 2.98g (K=39)
NaHCO3 6.72g (HCO3=61)
NaSO4 22.72g (SO4=96)

I'll do just the first part... You do all of these the same.

5840mg NaCl * (1mmol / 58.5mg) * (1mmol Na / 1mmol NaCl) * (1meq Na / 1mmol Na) = 99.9 Meq Na (from NaCL present)

Do the same process for NaHCO3 and NaSO4, and then add together to get the total number of Na Meqs present.

Rock the same style equations for NaCl and KCl to get the total K meqs...

 

[aboveliquidice]

if you have trouble with mw=g/mol and M=mol/l then i don't know how the rest of pharm school will be for you

I can't even remember where / when I learned dimensional analysis... I think 4th or 5th grade.

 

[Music Man]

Mother ******...I wrote out sodium sulfate as NaS04...that was the problem. Thanks.

 

[Music Man]

btw...dimensional analysis/stoichiometry on problems like these is ridiculously unnecessary and convoluted. All you need to do is divide wt/mEq. Why make life hard?

 

[aboveliquidice]

btw...dimensional analysis/stoichiometry on problems like these is ridiculously unnecessary and convoluted. All you need to do is divide wt/mEq. Why make life hard?

Because it's accurate...

 

[Music Man]

How is it more accurate than my method?

1mEq Na=58.5mg so

5840mg Na/58.5mg=99.8290598mEq

Just as accurate....

 

[aboveliquidice]

How is it more accurate than my method?

1mEq Na=58.5mg so

5840mg Na/58.5mg=99.8290598mEq

Just as accurate....

It assumes that the molar ratio is one to one... So you need to remember to adjust it for Ca... and then you need to adjust it further for millosmoles.

Whatever works best for ya

 

[Ackj]

Because it's accurate...

It assumes that the molar ratio is one to one... So you need to remember to adjust it for Ca

Yeah, better to be consistent imo. If you include the mmol to meq step even when its 1:1 you're less likely to forget the step when it isn't 1:1

 

[owlegrad]

btw...dimensional analysis/stoichiometry on problems like these is ridiculously unnecessary and convoluted. All you need to do is divide wt/mEq. Why make life hard?

Dimensional analysis is where it's at! Following units should come so natural that it should be like second-hand. Using short cuts are great as long as you can remember the formulas correctly, as well as under which situations they may be used. Better to just know the way that works 100% of the time and use it for everything. But whatever works for you I guess. Unnecessary and convoluted? Them's fighten' words!

 

[owlegrad]

I can't even remember where / when I learned dimensional analysis... I think 4th or 5th grade.

My Chem 1 professor actually took a little time before we started calculations for the first time in his class to review dimensional analysis.
I was like:

 

[johnconner]

How is it more accurate than my method?

1mEq Na=58.5mg so

5840mg Na/58.5mg=99.8290598mEq

Just as accurate....

The question asks how many mEq per liter. The answer thus far is incorrect. You should start off with 5.84g/4L * 1L to get the correct answer.

 

[Sparda29]

Seriously, where the **** do we ever use this ****? I haven't seen any mEq calculations in the hospital at all.

 

[IrishHammer]

Yeah, better to be consistent imo. If you include the mmol to meq step even when its 1:1 you're less likely to forget the step when it isn't 1:1

Okay great!

 

[aboveliquidice]

Seriously, where the **** do we ever use this ****? I haven't seen any mEq calculations in the hospital at all.

TPN fool... And any time you prepare a KCl drip (never hang more than 40 meq at a time).

Seriously - hanging too much KCL will kill someone.