wait...glucose(6c) => 2 PGAL(3c) then it loses CO2 to become acetyl CoA. So basically, only 2c enters the calvin cycle, right?
what are the product after the 1 cycle? is it just 2 PGAL(6c)? could u explain this part to me? If I remember it right, acetyl CoA(2C) meets oexaloacetate (4C) and becomes (6C) and that's the beginning of the Calvin Cycle. During the Cycle, it loses 2CO2 to make 2NAD+ into 2NADH and 2H+, so we end up with 4C in the end of the cycle. Am I wrong?
Even in the Kaplan's blue book, it says " through a complicated series of reactiosn, 2 CO2 are released, and oxloacetate(4C) is regenerated for use in another turn of the cycle." you said that each cycle produces 6C(since u said 2 PGAL are produced) and I don't know why it's not 4C.
and when u said "in reality, it produces 6 PGAL and only releases 1PGAL in 3 cycle" I don't understand it again. If the answer for my 1st question is 2PGAL for each cycle and 3 cycle makes 6PGAL, why does only 1 PGAL is released and where did other 5PGAL go?
so could u explain these 2 things for me ?