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If the following reaction is allowed to go to completion, what will the dominant product be?
Your Answer: 2−bromo−2−mehtylbutane
Correct Answer: 2−bromo−3−methylbutane
I thought this undergoes markovnikov addition and the Br would to the most substituted carbon, and the H goes to the least substituted, but the Kaplan ("Correct Answer") answer says otherwise...
Your Answer: 2−bromo−2−mehtylbutane
Correct Answer: 2−bromo−3−methylbutane
I thought this undergoes markovnikov addition and the Br would to the most substituted carbon, and the H goes to the least substituted, but the Kaplan ("Correct Answer") answer says otherwise...
