A boat can travel at 16 mph in still water. If it takes an hour and a half longer to go 45 miles upstream as downstream, what is the speed of the current?
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can someone help me solve this using equation
Started by per protocol
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speed = distance/time
let x = speed of the current
t = time taken for the boat to go downstream
upstream: (16 mph - x ) = (45miles)/( t + 1.5hrs)
downstream: (16 mph + x) = (45miles)/(t)
t = (45miles)/(16 mph +x)
so...
(16mph -x) = (45 miles)/([45miles/[16mph +x]] + 1.5 hrs)
so with an equation with one variable missing x = 4 mph.
let x = speed of the current
t = time taken for the boat to go downstream
upstream: (16 mph - x ) = (45miles)/( t + 1.5hrs)
downstream: (16 mph + x) = (45miles)/(t)
t = (45miles)/(16 mph +x)
so...
(16mph -x) = (45 miles)/([45miles/[16mph +x]] + 1.5 hrs)
so with an equation with one variable missing x = 4 mph.
So...it seems as though you post each of your questions twice.
I'd have to agree w/ Apollyon in All Students - the forum is not the place to do your homework or that of your kids.
Didn't you take physics or math??? I think if you go back to the chapter, you'll find it.
You know the saying....give a man a fish, you feed him for a day...teach him to fish............
or....maybe go back to All Students since this has nothing to do with a drug - oh, unless the boat is carrying illegal drugs😛
I'd have to agree w/ Apollyon in All Students - the forum is not the place to do your homework or that of your kids.
Didn't you take physics or math??? I think if you go back to the chapter, you'll find it.
You know the saying....give a man a fish, you feed him for a day...teach him to fish............
or....maybe go back to All Students since this has nothing to do with a drug - oh, unless the boat is carrying illegal drugs😛
What class is this???
Trial and error comes up with rate of 4 mph (12 upstream and 20 downstream)
Too bad someone already did the equation for you. Only took 4 trials and 3 errors.
are u in pharm program already? or pharmacist? this is easy algebra.
Wow o wow this forum is exciting. I was anticipating the rush of "can someone help with with this kinetics question" at the start of the year. But its March and now we are asking "can someone help me with this 5th grade algebra problem?" Nice.....
Kinetics really isn't that much different from 5th grade algebra to be honest.
