#35
total body fluid: 60% * 60L = 36L
total osmoles before administration = 36L * 260mosm/L = 9360
osmoles added = idk how to do this given their data...but I do know that 1L of 0.9nacl is 154mmol Na, so 2L of 3% is 1026na (and 1026cl) = 2052mosm
total osmoles after administration = 9360 + 2052 = 11412
total liters after admnistration = 36+2 = 38
osmolarity after= 11412/38 = 300.3
#36
ecf osmoles at start = 20% * 60L * 260= 3120mosm
osmoles added = 2052mosm
osmoles at end = 5172mosm
osmolarity from previous = 300mosm/L
ecf fluid after equilibration = 5172/300 = 17.24L