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Where is this problem from?
Maybe that carbon with the + is no longer sp2, so the benzene ring is no longer aromatic, therefore not stable?
I do understand that aromaticity is destroyed by having the positive charge on the benzene ring. But why is it less stable than primary carbocation?
It's called an aryl or phenyl carbocation. look closely - Aromaticity is *not* affected. The p orbital will be orthogonal (at right angles) to the p electrons of the ring - i.e. the empty p orbital will be where the hydrogen is.
It's more unstable than methyl because carbocations become less stable as you go from sp3 to sp2 to sp.
I would think that it will be more unstable than the vinyl carbocation drawn because there isn't a C-C bond to stabilize the carbocation through hyperconjugation, but it's subtle.
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Correct me if I'm wrong, there is no loss of aromaticity?
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the more the carbocation can resonate, the more stable it is because the charge can be delocalized with the other forms. so benzene is most stable then the alkene carbocation and then the methane carbocation.
Question is asking for Carbocation stability and Carbocation is most stable if its tertiary > secondary > primary > methlyl
Simply looking at the question we can come up with the answer III (Benzene b/c secondary carbon is carbocation) > II (Ethene b/c primary carbon is carbocation) > I (methyl b/c its methyl & the least stable carbocation)
OP, please advise what is the correct answer in the source where you got the question from?
RSD, that makes sense. Where do 1*, 2*, 3* fall in with sp, sp2, and sp3?
RSD, that makes sense. Where do 1*, 2*, 3* fall in with sp, sp2, and sp3?