Advertisement - Members don't see this ad
Hey, guys. I am a cardiology attending preparing for the CBCCT next month. I came across a question from the SCCT Board Question Prep Book and was wondering if anyone can help with the explanation and how they arrived at the answer so I can better understand the concept and the formula I need to know. Much thanks in advance.
Question:
A spiral CT scan and data reconstruction were performed with the following parameters:
• Detector collimation: 50 x 1 mm
• Rotation time: 500 ms
• Scan range: 20 cm
• Reconstructed field of view: 20 x 20 cm
• Reconstructed slice thickness: 0.8 mm
• Slice reconstruction increment: 0.5 mm
The heart rate of the patient at the time of the scan was 60 bpm. Approximately how many seconds was the scan time?
Answer: 8 seconds.
Explanation given: The table advances 50 mm * 0.25 = 12.5 mm per rotation, and 25 mm per second. To cover 20 cm will take 8 seconds.
Question:
A spiral CT scan and data reconstruction were performed with the following parameters:
• Detector collimation: 50 x 1 mm
• Rotation time: 500 ms
• Scan range: 20 cm
• Reconstructed field of view: 20 x 20 cm
• Reconstructed slice thickness: 0.8 mm
• Slice reconstruction increment: 0.5 mm
The heart rate of the patient at the time of the scan was 60 bpm. Approximately how many seconds was the scan time?
Answer: 8 seconds.
Explanation given: The table advances 50 mm * 0.25 = 12.5 mm per rotation, and 25 mm per second. To cover 20 cm will take 8 seconds.
