chem question - where did I go wrong?

[jackal head]

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If you haven't taken chem in a while you probably won't get this but whatever

"Oxalic acid, H2C2O4, occurs as the potassium or calcium salt in many plants, including rhubarb and spinach. An aqueous solution of oxalic acid is 0.602 m H2C2O4. The density of the solution is 1.022 g/mL. What is the molar concentration?"

Molar concentration = Molarity = moles of solvent / liters of solution

assume 1 L
1.022 g/mL = 1022 g/L

mm of H2c204
= 2 + 12(2) + 16(4) = 90

moles is given as .602 moles / 1kg

1L = 1kg in aqueous solution so why can't you now just do this

.602 moles of solute / 1.022 kg of solution?

 

[RaradX]

im in ochem2 and i would say the answer is (0.602 x 1.022 )/ 90=y,
y x 1000 = 6.84 moles/liter.


i would love to know if this is right or not

 

[161927]

0.602 mol acid/(kg soln)(1000 g/1 kg)(1 mL/1.022 g)(1 L/1000 mL) = 0.615 M

 

[tootoo30]

0.602 mol acid/(kg soln)(1000 g/1 kg)(1 mL/1.022 g)(1 L/1000 mL) = 0.615 M

That's the correct answer! I usually just knock out the step converting from g to ml, but that is basically how you do it. Good job 🙂