Why does the forward rate change faster than the reverse rate as the reaction proceeds?
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Chemical Equillibrium
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Are you talking about Keq and Q? If you're starting the reaction from the beginning, there are more reactants than products, so the overall reaction will move towards equilibrium (Keq=1). (If Q< Keq, it will move to the right, Q > Keq there are too many products and will go to the left).
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Are you asking why the forward reaction rate is FASTER, or why the forward reaction rate CHANGES FASTER?
Why the FWD rate is faster is because rate depends on concentration. In the beginning of a reaction, you have a very high concentration of reactants, which is why the fwd reaction rate if faster.
How the reaction rate changes (the derivative of the reaction rate) is probably beyond the scope of the MCAT.
Why the FWD rate is faster is because rate depends on concentration. In the beginning of a reaction, you have a very high concentration of reactants, which is why the fwd reaction rate if faster.
How the reaction rate changes (the derivative of the reaction rate) is probably beyond the scope of the MCAT.
