confused by neutralization...

[ilovemedi]

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I don't understand neutralization. I know moles H = moles OH, but how do you take the coefficiants into account?

For examlpe: how many mL of 0.2 H30+ are requried to neturazlie .02 mole of NaHCO3?

equation: NaHCO3+ H+ ----> Na + Co2 +H20

I thought it would be: V(.2)=(2*.02) since TWO hydrogens are formed from NaHCO3.. so you multiple the .02 above by 2..

 

[ilovemedi]

Ok so apparentl you look at the raitio of the reactatns.. so NaHCO3:H is 1:1.

Say you have .4 M NaOH with 100ml .25M H2SO4 to neutralize... HOW DO I FIGURE THIS OUT IF THEY DON'T WRITE OUT THE REACTION? srry caps on.

 

[sciencebooks]

I'm really tired at the moment which is preventing me from thinking about anything of these problems, lol, but could you use the equation M1V1=M2V2?

 

[indianjatt]

I don't understand neutralization. I know moles H = moles OH, but how do you take the coefficiants into account?

For examlpe: how many mL of 0.2 H30+ are requried to neturazlie .02 mole of NaHCO3?

equation: NaHCO3+ H+ ----> Na + Co2 +H20

I thought it would be: V(.2)=(2*.02) since TWO hydrogens are formed from NaHCO3.. so you multiple the .02 above by 2..

I think what's confusing you is knowing how many protons there are based off of the acid/bases given.

Here's how I would do it. If the question says how many Ml of an ACID are needed to neutralize say CO32-, you know right off the bat that Co32- must be the base... Being a base, it will accept protons. Now the KEY is to figure out exactly HOW many protons it can accept in order to get to it's neutral state. In the case of CO3 2-, you need 2 H+'s in order to neutralize CO3 2- into a neutral species, H2CO3. For HCO3 -, you need 1 H+ in order neutralize it (because the charge is -1) to H2CO3.

Same thing goes the opposite way. If you have a base, like OH- and you are neutralizing an acid, ask yourself, how many protons can this species lose. In your example you have H2So4.... well that has two protons it can lose, therefore, you have 2 H+ per mole of sulfuric acid. If you had Hso4-... well you only have 1 mole of H+ per mole of hso4-, so it would be neutralized by 1 mole of a monoprotic base.

I hope I helped. (sorry if it is somewhat unclear)

 

[Singhp03]

I don't understand neutralization. I know moles H = moles OH, but how do you take the coefficiants into account?

For examlpe: how many mL of 0.2 H30+ are requried to neturazlie .02 mole of NaHCO3?

equation: NaHCO3+ H+ ----> Na + Co2 +H20

I thought it would be: V(.2)=(2*.02) since TWO hydrogens are formed from NaHCO3.. so you multiple the .02 above by 2..

what was the answer?