confusing chem question

[issa]

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the answer is C so both are enantiomers.
can someone explain how to covert these into 2D fischer projections?

 

[IsRaEl21]

The Answer is correct the molecule on the left is R and on the right is S. therefore, they are enantiomers. It's very hard to explain it over the computer but my best suggestion is for U to open the Destroyer book on prob# 91. There are many problems like this in destroyer. DR. Romano developed the easiest and the best way to solve this problems. But as far I can help u over the computer the Object on the Left is R and on the Right is S Configuration. Destroyer will really help u not only with type of problem but with many others. I really don't like the way Kaplan explains it. So Good Luck to u!!! 👍👍👍

 

[Clubby]

issa, answer my PM!

That is all.


I'd help you with the question but the guy before me answered it,

 

[dentgirl08]

when it's a simple "4 armed molecule" (term i just made up) it's easy to figure out the R and S...

first is to find the lowest priority (in this case H) and see if it's sticking out towards you or in towards the paper (in this case the H are out towards you).

second is to find the spin (clockwise or counter) where spin goes from highest priority to lowest (in this case High - OH and lowest - methyl)

lets use your example...the left molecule has a spin going counter clockwise...but since H is sticking out towards you...reverse the spin. so instead of S it's R.

if the H was going into the page...the spin would be what you originally designated it as...

hope that helps.