C chickensoupdr Full Member 10+ Year Member Joined May 2, 2010 Messages 432 Reaction score 34 Mar 24, 2013 #1 Members don't see this ad. I understand how to recognize D and L isomers in hawthorn diagrams, but how are they recognized in the ring structures?
Members don't see this ad. I understand how to recognize D and L isomers in hawthorn diagrams, but how are they recognized in the ring structures?
sdm33 Full Member 10+ Year Member Joined Jan 1, 2013 Messages 178 Reaction score 3 Mar 24, 2013 #2 Right Down and Dirty Right = D In cyclic form Right = Down Upvote 0 Downvote
C chickensoupdr Full Member 10+ Year Member Joined May 2, 2010 Messages 432 Reaction score 34 Mar 24, 2013 #3 carbon 2? Upvote 0 Downvote
sdm33 Full Member 10+ Year Member Joined Jan 1, 2013 Messages 178 Reaction score 3 Mar 24, 2013 #4 Anamoric carbon in a cyclic form it bounds to two Oxygenes In Fischer projection of glucose it is carbon number 5 that determines D it OH to the right and L if OH to the left. Upvote 0 Downvote
Anamoric carbon in a cyclic form it bounds to two Oxygenes In Fischer projection of glucose it is carbon number 5 that determines D it OH to the right and L if OH to the left.
C chickensoupdr Full Member 10+ Year Member Joined May 2, 2010 Messages 432 Reaction score 34 Mar 25, 2013 #5 thank youu! Upvote 0 Downvote