DAT Achiever Chem Question

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dentalengineer

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What is the molality of 85% phosphoric acid, H3PO4, if the density of the solution is 1.70 g/ml?

I don't understant their explanation, could anyone explain how to solve the problem without paying attention to the given answers?

Thanks

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Molality means # of mole of solvent (H3PO4) dissolved in 1 kg of solvent (H2O).

From the density of solution given, let's choose 1 ml of solution which gives you 1.70 g of solution.

Now, an 85% solution means a ratio of 85 g of solute to 15 g of solvent, meaning also that out of the 1.70 g of solution chosen, there're (1.70 x 0.85) g of solute and (1.70 x 0.15) g of solvent. But remember you'll need to express the solvent weight in kg:

(1.70/1000) x 0.15 ---- (1)

Next, let's do the # of mole of solute:

(1.70/M.W.) x 0.85 ---- (2) where M.W. = molecular weight of solute

molility of solution : (2)/(1) = [(1.70/M.W.) x 0.85]/[(1.70/1000) x 0.15] = (1000 x 0.85) / (M.W. x 0.15)

Note: Answer expression in DAT Achiever has not been fully simplified.

Let me know if any of the above need further explanation...
 
yup this stuff is gonna be just as useful as knowing the reproductive organs of monocious plants and how they function through weird interrelated plant hormones
 
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