Molality means # of mole of solvent (H3PO4) dissolved in 1 kg of solvent (H2O).
From the density of solution given, let's choose 1 ml of solution which gives you 1.70 g of solution.
Now, an 85% solution means a ratio of 85 g of solute to 15 g of solvent, meaning also that out of the 1.70 g of solution chosen, there're (1.70 x 0.85) g of solute and (1.70 x 0.15) g of solvent. But remember you'll need to express the solvent weight in kg:
(1.70/1000) x 0.15 ---- (1)
Next, let's do the # of mole of solute:
(1.70/M.W.) x 0.85 ---- (2) where M.W. = molecular weight of solute
molility of solution : (2)/(1) = [(1.70/M.W.) x 0.85]/[(1.70/1000) x 0.15] = (1000 x 0.85) / (M.W. x 0.15)
Note: Answer expression in DAT Achiever has not been fully simplified.
Let me know if any of the above need further explanation...