D ddsshin Full Member 15+ Year Member Jul 25, 2009 #1 Advertisement - Members don't see this ad this is for G chem. what is the formula for 0 order and 2 order rate constant (k) regarding to half- life. how are they related to conc and time...??
Advertisement - Members don't see this ad this is for G chem. what is the formula for 0 order and 2 order rate constant (k) regarding to half- life. how are they related to conc and time...??
D ddsshin Full Member 15+ Year Member Jul 25, 2009 #2 can someone explain why these two compounds are not same and why they are enantiomers? Upvote 0 Downvote
sixkiller Full Member 10+ Year Member Jul 25, 2009 #3 zero order: [A] = -kt + [A]initial second order: 1/[A] = kt + 1/[A]initial Use the integrated rate laws to solve for the half life.... Upvote 0 Downvote
zero order: [A] = -kt + [A]initial second order: 1/[A] = kt + 1/[A]initial Use the integrated rate laws to solve for the half life....
D ddsshin Full Member 15+ Year Member Jul 25, 2009 #4 what is value of sin A if sin B is 1/4. there is a right triangle. A to C is 3 and C to B is 6. A is 90 degree. C is 60 degree. thx! Upvote 0 Downvote
what is value of sin A if sin B is 1/4. there is a right triangle. A to C is 3 and C to B is 6. A is 90 degree. C is 60 degree. thx!
U UCB05 Full Member 15+ Year Member Jul 25, 2009 #5 ddsshin said: what is value of sin A if sin B is 1/4. there is a right triangle. A to C is 3 and C to B is 6. A is 90 degree. C is 60 degree. thx! Click to expand... Not possible. If A is a right angle and C is 60 degrees, you'd have a 30-60-90 right triangle and sin B would be 1/2 and sin A would be 1. Either the question is wrong or you're reading it wrong. Upvote 0 Downvote
ddsshin said: what is value of sin A if sin B is 1/4. there is a right triangle. A to C is 3 and C to B is 6. A is 90 degree. C is 60 degree. thx! Click to expand... Not possible. If A is a right angle and C is 60 degrees, you'd have a 30-60-90 right triangle and sin B would be 1/2 and sin A would be 1. Either the question is wrong or you're reading it wrong.
