Highhopee, how are you getting the formula "base formula with N = C5H13N (2)"?
I know you can C5H12 from Cn Hn+2 and based on this I am using this formula and subtracting it from C5H5N means 12 from the alkane formula subtract it from 5H and 1N
12 - 6 = 6 / 2 = 3 degree of unsaturation. I know the answer is wrong and I understand using C2H13N would give me the correct answer but where is this formula coming from because
alkane = Cn Hn+2
alkene = Cn Hn
alkyne = Cn Hn-2
Hey Ibraiz
I'll show you step by step,
To find Unsaturation for C5H5N,
First find the base formula, meaning find the molecular formula
that is an alkane with C = 5 and associated amount of Hydrogens.
This is easy to find because you know that the ends will have 3 hydrogens and the middle methylenes have 2 hydrogens.
So it is (2x3H) + (3x2H) = 12H
Thus, we have C5H12
Now, find the base formula with 1 Nitrogen.
For group V (N, P, As, Sb, Bi), add 1H to your base formula because
if we have CH and attach N, we get CNH2
We went from 1H to 2H, meaning we add 1 H.
For group VI (O, S, Se, Te),
we don't add nor subtract Hydrogens because
if we have CH and add O, we get COH
There is no change in # of hydrogens.
For group VII (F, Cl, Br, I),
we subtract 1H because
if we add these atoms, we go from CH to CF
There is a change in number of hydrogens from 1H to 0.
So our base formula was C5H12.
Add 1N. Thus we now have C5H13N
Subtract the # of hydrogens that we get with N (C5H13N)
to the # of hydrogens that was asked (C5H5N)
13 - 5 = 8
Now, divide 8 by 2.
Voila, our degree of unsaturation is 4! =)