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Destroyer Ochem #138

Discussion in 'DAT Discussions' started by Predentknight, May 30, 2008.

  1. Predentknight

    5+ Year Member

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    Take a look at step 2 in the synthesis problem. I understand that it is an E2 elimination but I do not understand why it would form the less substituted alkene? Anybody with destroyer who understands this problem, please explain.
     
  2. drtoothy

    2+ Year Member

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    tBuO-K+ is used -- any bulky base won't sterically be able to form the most substituted product. therefore, the primary halide forms.
     

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