Destroyer Ochem #138

[Predentknight]

Take a look at step 2 in the synthesis problem. I understand that it is an E2 elimination but I do not understand why it would form the less substituted alkene? Anybody with destroyer who understands this problem, please explain.

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[drtoothy]

tBuO-K+ is used -- any bulky base won't sterically be able to form the most substituted product. therefore, the primary halide forms.