Destroyer Ochem #138

Started by Predentknight
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Predentknight

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Take a look at step 2 in the synthesis problem. I understand that it is an E2 elimination but I do not understand why it would form the less substituted alkene? Anybody with destroyer who understands this problem, please explain.
 
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tBuO-K+ is used -- any bulky base won't sterically be able to form the most substituted product. therefore, the primary halide forms.
 
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