destroyer ochem question #131

Started by pidbull
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pidbull

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Hi guys,

I had problems with 131. It says in the solution that a secondary halide treated with a strong, big bulky base yields the less substituted alkene (E2). I don't get that, can someone shed some light on that concept and maybe explain other scenarios like tertiary halide? Is this some kind of rule? Thanks
 
primary and secondary halide with a big, bulkey strong base gives E2 and the product is the least substituted. this is a rule, remember it